我有一个数据框,
DF,
Name Stage Description
Sri 1 Sri is one of the good singer in this two
2 Thanks for reading
Ram 1 Ram is one of the good cricket player
ganesh 1 good driver
和一个清单,
my_list=["one","driver"]
I tried, names=df.loc[df["Description"].str.contains("|".join(my_list),na=False), 'Name']
除了keyvalue列之外,实现了一切。
output_DF.
Name Stage Description
Sri 1 Sri is one of the good singer in this two
Ram 1 Ram is one of the good cricket player
My desired output is,
desired_DF,
Name Stage Description keyvalue
Sri 1 Sri is one of the good singer in this two one
2 Thanks for reading
Ram 1 Ram is one of the good cricket player one
ganesh 1 good driver driver
有人帮我生成keyvalue列
答案 0 :(得分:2)
我认为您可以使用here之前的解决方案,然后使用extract
:
pat = "|".join(my_list)
df['keyvalue'] = df['Description'].str.extract("(" + pat + ')', expand=False).fillna('')
print (df)
Name Stage Description keyvalue
0 Sri 1 Sri is one of the good singer in this two one
1 Sri 2 Thanks for reading
2 Ram 1 Ram is one of the good cricket player one
3 ganesh 1 good driver driver
所有在一起:
print (df)
# Name Stage Description
#0 Sri 1 Sri is one of the good singer in this two
#1 2 Thanks for reading
#2 Ram 1 Ram is one of the good cricket player
#3 ganesh 1 good Driver one
my_list=["ONE","driver"]
df['Name'] = df['Name'].mask(df['Name'].str.strip() == '').ffill()
pat = "|".join(my_list).lower()
names=df.loc[df["Description"].str.lower().str.contains(pat,na=False), 'Name']
df = df[df['Name'].isin(names)]
df['keyvalue'] = (df['Description'].str.lower()
.str.extract("(" + pat + ')', expand=False)
.fillna(''))
print (df)
# Name Stage Description keyvalue
#0 Sri 1 Sri is one of the good singer in this two one
#1 Sri 2 Thanks for reading
#2 Ram 1 Ram is one of the good cricket player one
#3 ganesh 1 good Driver one driver