我正在尝试使用反应路由器,但我遇到了麻烦。当我点击链接时,我希望它消失以前的数据,只显示当前数据。但在我的情况下,它似乎两个数据,我也无法通过网址访问。有人能帮助我吗?
我正在尝试使用反应路由器,但我遇到了麻烦。当我点击链接时,我希望它消失以前的数据,只显示当前数据。但在我的情况下,它似乎两个数据,我也无法通过网址访问。有人能帮助我吗?
我的代码:
import React, {Component} from 'react'
import axios from 'axios'
import ShotList from './shotList'
const URL = 'https://api.dribbble.com/v1/shots/'
const token = 'token'
export default class Shots extends Component{
constructor(props){
super(props)
this.state = {list: []}
this.getShots()
}
getShots(){
axios.get(`${URL}?access_token=${token}`)
.then(resp => this.setState({...this.state, list: resp.data} ))
}
render(){
return(
<div>
<ShotList list={this.state.list}/>
</div>
)
}
}
import React from 'react'
import {BrowserRouter as Router, Route, Link} from 'react-router-dom'
export default props =>{
const renderRows = () =>{
const list = props.list || []
JSON.stringify(list)
return list.map(shots =>(
<Router key={shots.id}>
<div >
<Link to={`/shots/${shots.id}`}>
<div className='col-md-3 col-sm-4 col-xs-6 teste'>
<img src={shots.images.normal} className='img-responsive' />
<p>{shots.views_count}</p>
</div>
</Link>
<Route path="/shots/:shotsId" component={Detail}/>
</div>
</Router>
))
}
const Detail = ({match}) =>{
return(
<div>
{match.params.shotsId}
</div>
)
}
return(
<div>
{renderRows()}
</div>
)
}
答案 0 :(得分:1)
您只需要1 Router
进行路由,而不是为每个行创建新的Router
。您需要使用Switch
仅渲染选定的Route
。您renderRows
的代码可以修改如下。
import React from 'react'
import {BrowserRouter as Router, Route, Switch, Link} from 'react-router-dom'
export default props =>{
const renderRows = () =>{
const list = props.list || []
JSON.stringify(list)
return (
<Router>
<div>
{list.map(shots =>
<Link to={`/shots/${shots.id}`}>
<div className='col-md-3 col-sm-4 col-xs-6 teste'>
<img src={shots.images.normal} className='img-responsive' />
<p>{shots.views_count}</p>
</div>
</Link>) }
<Switch>
{list.map(shots =><Route path="/shots/:shotsId" component={Detail}/>)}
</Switch>
</div>
</Router>);
}
编辑:收到评论后修正了代码中的错误。