我有两个组件,我想显示未找到的页面,但是问题是,我不想在NotFound
内调用<switch>
组件,因为我的开关在标题和侧边栏中。
请参阅组件代码。
App.js
import React, {Component} from 'react';
import Header from './Header.js';
import Main from './Main.js';
import { Switch, Route, Redirect } from 'react-router-dom';
class App extends Component
{
constructor(){
super();
}
render(){
return (
<Switch>
<Route path="/" component={Main} />
</Switch>
)
}
}
export default App;
我的下一个组件Main.js
import React, {Component} from 'react';
import Header from '../app/Header.js'
import Integration from '../app/Integration.js';
import History from '../app/History';
import { Switch, Route } from 'react-router-dom'
import Dashboard from './Dashboard';
import List from '../config/List'
import NotFound from './NotFound';
class Main extends Component
{
constructor(){
super();
}
render(){
return (
<div>
<Header/>
<div className="content">
<History/>
<div className="main-content">
<Switch>
<Route exact path="/configuration" component={List} />
<Route exact path="/configuration/show" component={Dashboard} />
// I don't want to put my NotFound Route Tag here, because it includes header and sidebar */
</Switch>
</div>
<Integration/>
</div>
</div>
)
}
}
export default Main
答案 0 :(得分:0)
我已经解决了。
第1步:在主组件中创建了一个功能
renderWithLayout = (component) => {
return (<div>
<Header/>
<div className="content">
<History/>
<div className="main-content">
{component}
</div>
<Integration/>
</div>
</div>)
};
第二步:修改了主要组件的渲染方法
render(){
return (
<Switch>
<Route exact path="/configuration" render={(props) => {
return this.renderWithLayout(<List {...props}/>) ;
}} />
<Route exact path="/configuration/show" render={(props)=>{
return this.renderWithLayout(<Dashboard {...props}/>);
}} />
<Route path="*" component={NotFound}/>
</Switch>
)
}
无论如何。谢谢您的努力:)