如何将我的掷骰子代码的输出添加到数组my_list? 我希望最终输出看起来像:
1's: {No. Of One's}
2's: {No. Of Two's}
3's: {No. Of Three's}
4's: {No. Of Four's}
显然在打印出游戏输出后 我尝试将数据行的追加添加到底部,然后打印my_list以执行此操作,以便它在之后运行但无法正常工作
我的代码如下所示:
my_list = []
for i in range(1,2):
def RollDice():
import random
d1 = random.randint(1, 6)
d2 = random.randint(1, 6)
return int(d1 + d2)
def ComeOutRoll():
print('Come-Out Roll')
roll = RollDice()
if roll in [7, 11]:
print('You win!')
elif roll in [2,3,12]:
# craps lose
print('Craps! You lose!')
elif roll in [4,5,6,8,9,10]:
# the point
print('Point %d' % roll)
Finished = False
while not Finished: Finished = ReRoll(roll)
def ReRoll(point):
roll = RollDice()
print(' Roll: %d' % (roll))
if not roll in [7, point]:
# lose
print('Roll again!')
elif roll in [point]:
# point match
print('Point-Match')
elif roll in [7]:
# seven-out lose
# game over
print('Seven-Out!\nYou lose!\nGame Over!')
return True
return False
ComeOutRoll()
my_list.append(RollDice)
print(my_list)
Output:
Come-Out Roll
You win!
[<function RollDice at 0x000000CAEFAAFAE8>]
答案 0 :(得分:0)
试试这个
my_list = []
my_num = []
for i in range(1,2):
def RollDice():
import random
d1 = random.randint(1, 6)
d2 = random.randint(1, 6)
UpdArray(d1)
UpdArray(d2)
return int(d1+d2)
def UpdArray(x):
my_num.append(x)
def ComeOutRoll():
print('Come-Out Roll')
roll = RollDice()
if roll in [7, 11]:
print('You win!')
elif roll in [2,3,12]:
# craps lose
print('Craps! You lose!')
elif roll in [4,5,6,8,9,10]:
# the point
print('Point %d' % roll)
Finished = False
while not Finished: Finished = ReRoll(roll)
def ReRoll(point):
roll = RollDice()
print(' Roll: %d' % (roll))
if not roll in [7, point]:
# lose
print('Roll again!')
elif roll in [point]:
# point match
print('Point-Match')
elif roll in [7]:
# seven-out lose
# game over
print('Seven-Out!\nYou lose!\nGame Over!')
return True
return False
ComeOutRoll()
my_list.append(RollDice())
print(my_list)
print("req. ", my_num)
for x in set(my_num):
print(x,"'s", my_num.count(x), "\n" )
示例输出:
Come-Out Roll
Point 10
Roll: 7
Seven-Out!
You lose!
Game Over!
[9]
req. [4, 6, 6, 1, 3, 6]
1 's 1
3 's 1
4 's 1
6 's 3