Question

我写了一个示例脚本，它将字符串拆分为多个变量

#!/bin/bash
IN="One-XX-X-17.0.0"
IFS='-' read -a ADDR <<< "$IN"
for i in "${ADDR[@]}"; do
    echo "${ADDR[i]}"
done

while IFS='.' read -a ADDR[3]; do
      for i in "${ADDR[3]}"; do
           process "$i"
done

如var11 = 1，var12 = XX，var13 = X，major1 = 17，minor1 = 0，rel1 = 0

但每次运行此脚本时都会收到错误。有人能告诉我我的剧本有什么问题

Answer 1

#!/bin/bash
IN="One-XX-X-17.0.0"
IFS='-' read -a ADDR <<< "$IN"
for i in "${ADDR[@]}"; do
    echo "$i"
done
#split 17.0.0 into NUM
IFS='.' read -a NUM <<<${ADDR[3]};
for i in "${NUM[@]}"; do
    echo "$i"
done

输出：

One
XX
X
17.0.0
17
0
0

<强> UPD

#same code
#array of names of variable
var=(major minor rel)

#split 17.0.0 into NUM
IFS='.' read -a NUM <<<${ADDR[3]};

for((i=0;i<${#NUM[@]};i++)); do
    #assign
    eval ${var[$i]}=${NUM[$i]}
done
#now test
echo $major
echo $minor 
echo $rel

输出：

17
0
0

使用IFS示例拆分字符串

1 个答案: