Question

正如我在cakephp 3.x中所做的那样，我可以通过一个有计数的行对结果进行排序，因为我看不到表单，CakePHP 2.x中非常类似的东西没有问题。缺少什么能够在CakePHP 3.x中做同样的事情？我的测试是PHP 7.1 WAMP中的CakePHP v3.3.10

除了最终的 count_users 之外，所有类型的分页都能正常工作，当我点击它时不会出错，只是不对数据进行排序。

HTML ctp

<?= $this->Paginator->sort('count_users',_('N° Users')); ?>

控制器

    $this->Licensees->schema()
        ->addColumn('count_users', [
            'type' => 'integer',
        ]);
    $this->Licensees->aliasField('count_users');

    $where = [
        'recursive'=>-1,
        'fields' => [
           'Licensees.id',
           'Licensees.name',
           'Licensees.created',
           'Licensees.modified',
           'Licensees__count_users' => 'count(LicenseesUsers.licensees_id)',
           // 'count_users' => 'count(LicenseesUsers.licensees_id)', 
           // 'Licensees.count_users' => 'count(LicenseesUsers.licensees_id)', 
         ],
        'sortWhitelist' => ['name','count_users','created','modified'],
        'join' => [
            'LicenseesUsers' => [
                'table' => 'licensees_users',
                'type' => 'LEFT',
                'conditions' => [
                    'LicenseesUsers.licensees_id = Licensees.id'
                ],
            ],
        ],
        'group' => 'Licensees.id'
    ];

     // Set pagination
    $this->paginate = $where;

    // Get data
    $licensees = $this->paginate($this->Licensees);

显示错误排序分页字段count_users

object(Cake\ORM\Query) {

    '(help)' => 'This is a Query object, to get the results execute or iterate it.',
    'sql' => 'SELECT Licensees.id AS `Licensees__id`, Licensees.name AS `Licensees__name`, Licensees.created AS `Licensees__created`, Licensees.modified AS `Licensees__modified`, count(LicenseesUsers.licensees_id) AS `Licensees__count_users`, count(LicenseesUsers.licensees_id) AS `count_users` FROM licensees Licensees LEFT JOIN licensees_users LicenseesUsers ON LicenseesUsers.licensees_id = Licensees.id LEFT JOIN users Users ON Users.id = LicenseesUsers.users_id GROUP BY Licensees.id  ORDER BY Licensees.count_users asc LIMIT 50 OFFSET 0',
    'params' => [],
    'defaultTypes' => [
        'Licensees__id' => 'uuid',
        'Licensees.id' => 'uuid',
        'id' => 'uuid',
        'Licensees__name' => 'string',
        'Licensees.name' => 'string',
        'name' => 'string',
        'Licensees__active' => 'boolean',
        'Licensees.active' => 'boolean',
        'active' => 'boolean',
        'Licensees__deleted_at' => 'datetime',
        'Licensees.deleted_at' => 'datetime',
        'deleted_at' => 'datetime',
        'Licensees__created' => 'datetime',
        'Licensees.created' => 'datetime',
        'created' => 'datetime',
        'Licensees__modified' => 'datetime',
        'Licensees.modified' => 'datetime',
        'modified' => 'datetime',
        'Licensees__count_users' => 'integer',
        'Licensees.count_users' => 'integer',
        'count_users' => 'integer'
    ],
    'decorators' => (int) 0,
    'executed' => false,
    'hydrate' => true,
    'buffered' => true,
    'formatters' => (int) 0,
    'mapReducers' => (int) 0,
    'contain' => [],
    'matching' => [],
    'extraOptions' => [
        'recursive' => (int) -1,
        'scope' => null,
        'sortWhitelist' => [
            (int) 0 => 'name',
            (int) 1 => 'count_users',
            (int) 2 => 'created',
            (int) 3 => 'modified'
        ],
        'whitelist' => [
            (int) 0 => 'limit',
            (int) 1 => 'sort',
            (int) 2 => 'page',
            (int) 3 => 'direction'
        ]
    ],
    'repository' => object(App\Model\Table\LicenseesTable) {

        'registryAlias' => 'Licensees',
        'table' => 'licensees',
        'alias' => 'Licensees',
        'entityClass' => 'App\Model\Entity\Licensee',
        'associations' => [
            [maximum depth reached]
        ],
        'behaviors' => [
            [maximum depth reached]
        ],
        'defaultConnection' => 'default',
        'connectionName' => 'default'

    }

}

Answer 1

正如评论中所提到的，你必须使用count_users变体，即没有任何别名，这通常会正常工作。

因为你已经在你的模式（count_users）中创建了$this->Licensees->schema()->addColumn()列部分，所以会破坏你的东西，这将导致CakePHP将其视为真正的列，因此它将在内部别名列名称将导致ORDER BY子句使用Licensees.count_users，这将不起作用，因为不存在此列（您不能将计算列添加到现有别名）。

如果您需要将计算列视为特定类型，则通过创建和分页正确的查询对象，或者通过动态修改查询（例如查找程序）来修改（select）类型映射，或通过Model.beforeFind事件。

// use getSelectTypeMap() as of CakePHP 3.4
$query->selectTypeMap()->addDefaults([
    'count_users' => 'integer'
]);

另见

的 API > \Cake\Database\Query::selectTypeMap()

的 API > \Cake\Database\TypeMap

的 Cookbook > Controllers > Pagination

的 Cookbook > ORM > Retrieving Data & Results Sets > Custom Finder Methods

的 Cookbook > ORM > Table Objects > Lifecycle Callbacks > beforeFind

的 Cakephp-3.x: How to change the data type of a selected alias?

Answer 2

感谢ndm ，这就是你所说的。

问题将在以下几行中进行评论。

<强>控制器：

//    $this->Licensees->schema()
//            ->addColumn('count_users', [
//                'type' => 'integer',
//            ]);
//        $this->Licensees->aliasField('count_users');

$where = [
        'recursive'=>-1,
        'fields' => [
           'Licensees.id',
            'Licensees.name',
            'Licensees.created',
            'Licensees.modified',
//            'Licensees__count_users' => 'count(LicenseesUsers.licensees_id)',
            'count_users' => 'count(LicenseesUsers.licensees_id)', 
         ],
        'sortWhitelist' => ['name','count_users','created','modified'],
        'join' => [
            'LicenseesUsers' => [
                'table' => 'licensees_users',
                'type' => 'LEFT',
                'conditions' => [
                    'LicenseesUsers.licensees_id = Licensees.id'
                ],
            ],
        ],
        'group' => 'Licensees.id'
    ];

     // Set pagination
    $this->paginate = $where;

    // Get data
    $licensees = $this->paginate($this->Licensees);

排序Pagination by，行Alias Count，例如在CakePHP 3.x中，通过链接连接表来计算数据

2 个答案: