我在下面的代码中遇到了行数问题。这意味着,在每个页面中的分页行中,从头开始计算。例如,明确:
P1:如果我们在分页的第一页上,则行数是:
1 Columns1
2 Columns2
3 Columns3
4 Columns4
P2:如果我们在分页的第一页上,则行是计数:
1 Columns1
2 Columns2
3 Columns3
4 Columns4
我需要继续行计数为1234 5678 我使用这个代码
$sql = mysql_query("select * from (two_make left join two_model on two_make.make_id = two_model.make_id) left join two_variant on two_model.model_id = two_variant.model_id;");
$nr = mysql_num_rows($sql);
if (isset($_GET['pn'])) {
$pn = preg_replace('#[^0-9]#i', '', $_GET['pn']);
} else {
$pn = 1;
}
$itemsPerPage = 20;
$lastPage = ceil($nr / $itemsPerPage);
if ($pn < 1) {
$pn = 1;
} else if ($pn > $lastPage) {
$pn = $lastPage;
}
$centerPages = "";
$sub1 = $pn - 1;
$sub2 = $pn - 2;
$add1 = $pn + 1;
$add2 = $pn + 2;
if ($pn == 1) {
$centerPages .= ' <span class="pagNumActive">' . $pn . '</span> ';
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $add1 . '">' . $add1 . '</a> ';
} else if ($pn == $lastPage) {
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $sub1 . '">' . $sub1 . '</a> ';
$centerPages .= ' <span class="pagNumActive">' . $pn . '</span> ';
} else if ($pn > 2 && $pn < ($lastPage - 1)) {
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $sub2 . '">' . $sub2 . '</a> ';
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $sub1 . '">' . $sub1 . '</a> ';
$centerPages .= ' <span class="pagNumActive">' . $pn . '</span> ';
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $add1 . '">' . $add1 . '</a> ';
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $add2 . '">' . $add2 . '</a> ';
} else if ($pn > 1 && $pn < $lastPage) {
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $sub1 . '">' . $sub1 . '</a> ';
$centerPages .= ' <span class="pagNumActive">' . $pn . '</span> ';
$centerPages .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $add1 . '">' . $add1 . '</a> ';
}
$limit = 'LIMIT ' .($pn - 1) * $itemsPerPage .',' .$itemsPerPage;
$sql2 = mysql_query("select * from (two_make left join two_model on two_make.make_id = two_model.make_id) left join two_variant on two_model.model_id = two_variant.model_id ORDER BY make ASC $limit");
$paginationDisplay = "";
if ($lastPage != "1"){
$paginationDisplay .= 'Page <strong>' . $pn . '</strong> of ' . $lastPage. ' ';
if ($pn != 1) {
$previous = $pn - 1;
$paginationDisplay .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $previous . '"> Back</a> ';
}
$paginationDisplay .= '<span class="paginationNumbers">' . $centerPages . '</span>';
if ($pn != $lastPage) {
$nextPage = $pn + 1;
$paginationDisplay .= ' <a href="' . $_SERVER['PHP_SELF'] . '?pn=' . $nextPage . '"> Next</a> ';
}
}
$outputList = ''; ?>
<form name="form1" method="POST" action="">
<table width="578" border="1" align="center" id="menu">
<h3 style="color:#68ADD4;"><u>Two Wheeler List</u></h3>
<tr>
<th style="color:#68ADD4;">Si.no</th>
<th style="color:#68ADD4;">Make</th>
<th style="color:#68ADD4;">Model</th>
<th style="color:#68ADD4;">Variant</th>
<th style="color:#68ADD4;">Select</th>
</tr>
<?php
$i=0;
while($row=mysql_fetch_array($sql2))
{
$i++;
?>
<tr>
<td><?php echo $i ;?></td>
<td><?php echo $row['make'];?></td>
<td><?php echo $row['model'];?></td>
<td><?php echo $row['variant'];?></td>
<td><center><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['variant_id'];?>"></center></td>
</tr>
<?php } ?>
答案 0 :(得分:1)
而不是echo $ i;
echo(($ itemsPerPage * $ pn)+ $ i);
其中$ itemsPerpage是每页的项目数,$ pn是您的页码