这是我的代码:
from threading import Thread
from time import sleep
from msvcrt import getch
key = 0
def ProcessKey(key):
if key == 97:
return 1
elif key == 32:
return 2
elif key == 13:
return 3
else:
return 0
def Check():
sleep(2)
if key != 0:
return
Thread(target = Check()).start()
key = ord(getch())
print(ProcessKey(key))
定时输入在切断某人输入输入时工作正常,但如果有人及时输入输入,我必须在执行下一行代码之前等待整整2秒。在有人输入输入后,如何跳过剩下的2秒钟?
答案 0 :(得分:0)
from threading import Thread
from time import sleep
from msvcrt import getch
key = 0
def ProcessKey(key):
if key == 97:
return 1
elif key == 32:
return 2
elif key == 13:
return 3
else:
return 0
def Check():
sleep(2)
if key != 0:
return
Thread(target = Check).start() ##Dont call the function just enter the name I think this will solve
key = ord(getch())
print(ProcessKey(key))