Question

下面的python代码有一个TKinter gui，可以更新计算函数中的内容（最后用self.after（）调用自身.GUI还有一些滑块，用户将在能够调整参数。计算中有一个睡眠延迟，这就是问题：代码运行良好，除了time.sleep（1）不仅阻塞了1秒的计算，还阻止了GUI本身：它＆＃ 39; s只能每秒移动滑块然后一切都被阻塞一秒钟。我能做什么time.sleep（1）只能使计算功能休眠，而不是GUI本身？我需要运行吗？计算函数在一个单独的线程中？

import Tkinter as tk
import ttk
import time

class GUI(tk.Frame):
    def __init__(self, master=None):
        tk.Frame.__init__(self, master)
        self.pack()
        self.i=0
        self.var1 = tk.StringVar()
        self.var2 = tk.StringVar()
        self.var3 = tk.StringVar()
        self.var4 = tk.StringVar()
        self.var5 = tk.StringVar()
        self.var6 = tk.StringVar()
        self.var7 = tk.StringVar()
        tk.Label(self, textvariable=self.var1,justify='left').pack()
        tk.Label(self, textvariable=self.var2).pack()
        tk.Label(self, textvariable=self.var3).pack()
        tk.Label(self, textvariable=self.var4).pack()
        tk.Label(self, textvariable=self.var5).pack()
        tk.Label(self, textvariable=self.var6).pack()
        tk.Label(self, textvariable=self.var7).pack()


        p1 = tk.Scale(master, from_=1, to=20, orient=tk.HORIZONTAL).pack()
        p2 = tk.Scale(master, from_=1, to=20, orient=tk.HORIZONTAL).pack()
        p3 = tk.Scale(master, from_=1, to=20, orient=tk.HORIZONTAL).pack()
        p4 = tk.Scale(master, from_=1, to=20, orient=tk.HORIZONTAL).pack()
        p5 = tk.Scale(master, from_=1, to=20, orient=tk.HORIZONTAL).pack()

        self.progress = ttk.Progressbar(self, orient="horizontal",length=100, mode="determinate")
        self.progress.pack()

    def calculation(self):
        # complex calculations that last 30 minutes in total
        self.i += 1
        time.sleep(1)
        max=1000
        self.var1.set("Value1: "+str(self.i))
        self.var2.set("Value2: "+str(self.i+100))
        self.var3.set("Value3: "+str(self.i+100))
        self.var4.set("Value4: "+str(self.i+100))
        self.var5.set("Value5: "+str(self.i+100))
        self.var6.set("Value6: "+str(self.i+100))
        self.var7.set("Value7: "+str(self.i+100))
        self.progress["value"] = int(round(self.i*100/max))
        #self.update()  # no need, will be automatic as mainloop() runs
        self.after(1, self.calculation)

app=GUI()
app.calculation()  # start calculations
app.mainloop()  # run gui

Answer 1

如果你绝对必须使用睡眠，那么是的，计算应该在另一个线程或另一个进程中完成。

Tkinter有after和time.sleep

1 个答案: