Question

想知道是否有一种简单的方法来做我尝试的事情和最好的方式来做这样的事情。

answer=y 
while [ "$answer" = y ]
do 
    echo "type name of the file you wish to delete"
    IFS= read -r file
    echo "would you like to delete another file [y/n]?"
    IFS= read -r answer
done 

echo "Exiting Program"
exit 0

我在这里的问题是当输入输入时它存储在文件中但我希望当答案为y时它可以存储到另一个变量如file1。然后我留下了包含有人希望删除的所有文件名的变量，我可以回复。

如何在此处使用循环来继续添加输入，直到某人键入n

感谢您的帮助。

Answer 1

我不会使用实时读取循环来删除文件。太多事情都可能出错。相反，可以采取输入文件并检查每个。

但是对于你的问题的简单回答 -

typeset -l answer=y  # force to lowercase
lst=/tmp/file.list.$$
while [[ "$answer" = y ]]
do 
    echo "type name of the file you wish to delete"
    IFS= read -r file
    if [[ -e "$file" ]]
    then echo "$file" >> $lst
    else echo "That file does not exist/is not accessible."
    fi
    echo "would you like to delete another file [y/n]?"
    IFS= read -r answer
done 
echo -e "Files to be deleted:\n===\n$(<$lst)"
echo -e "\n===\n Delete all listed files [y/n]?"
IFS= read -r answer
if [[ y = "$answer" ]]
then rm $(<$lst)
fi
rm $lst

Answer 2

也许这会有所帮助：

while :; do
    read -s -n 1 answer
    if [ $answer = "y" ||  $answer = "Y" ]; then <your code>
    elif [ $answer = "n" ||  $answer = "N" ]; then echo; echo; break
    elif [ $answer = "" ]; then continue                # pressed: return key
    fi
  done

取决于您使用的shell，您可以使用：[[$ {answer} =〜（Y | y）]]

bash脚本while循环，带有来自用户的读取输入

2 个答案: