我需要第二个用户无法看到第一个用户的输入,但当它告诉第二个用户输入时,第一个用户的输入就在他们面前
score=[0,0]
print("Welcome to Rock Paper Scissors! The score starts as",score)
while True:
player1=input("Player 1's turn: ")
player2=input("Player 2's turn: ")
if (player1.lower() in ["rock","r","rick","rok","roc","rck"]):
if (player2.lower() in ["scissors","s","scissor"]):
score[0]=score[0]+1
print("Player 1 wins! The score is now",score)
if (player2.lower() in ["rock","r","rick","rok","roc","rck"]):
print("It's a tie! The score remains",score)
if (player2.lower() in ["paper","p","pap","piper"]):
score[1]=score[1]+1
print("Player 2 wins! The score is now",score)
if (player1.lower() in ["scissors","s","scissor"]):
if (player2.lower() in ["scissors","s","scissor"]):
score[0]=score[0]+0
print("It's a tie! The score remains",score)
if (player2.lower() in ["rock","r","rick","rok","roc","rck"]):
score[1]=score[1]+1
print("Player 2 wins! The score is now",score)
if (player2.lower() in ["paper","p","pap","piper"]):
score[0]=score[0]+1
print("Player 1 wins! The score is now",score)
if (player1.lower() in ["paper","p","pap","piper"]):
if (player2.lower() in ["scissors","s","scissor"]):
score[1]=score[1]+1
print("Player 2 wins! The score is now",score)
if (player2.lower() in ["rock","r","rick","rok","roc","rck"]):
score[0]=score[0]+1
print("Player 1 wins! The score is now",score)
if (player2.lower() in ["paper","p","pap","piper"]):
score[0]=score[0]+0
print("It's a tie! The score remains",score)
print("N E X T G A M E")
输出结果为:
Player 1's turn: r
Player 2's turn:
现在,玩家2只会使用纸张赢得比赛,所以我需要隐藏哪个玩家1以某种方式输入(我使用的是Python 3.6.1)
答案 0 :(得分:1)
我正在使用Visual Studio代码编辑器,当我运行此代码时,它将清除“终端”窗口,该窗口将在不执行该命令的情况下执行。
AS ['+@DynamicColumnName+']
答案 1 :(得分:0)
您可以在此处使用getpass
隐藏播放器1的输入,并使用input()
为第二个玩家输入。
import getpass
player1 = getpass.getpass(prompt = "Player 1's turn:")
player2 = input("Player 2's turn")
答案 2 :(得分:0)
您可以尝试从控制台中删除所有文本,然后再询问播放器2的输入。
- hence I then tried to recompiled it with the provided Makefile but I get a whole buch of errors (pages or errors). So My intention was to fire up
请注意,如果在Windows上使用IDLE,此解决方案将无效,因为import os
player1=input("Player 1's turn: ")
os.system('cls')
player2 = input("Player 2's turn: ")
不会与IDLE shell进行交互(this Stackoverflow answer中的更多详细信息)。
为此,你最好的选择似乎是打印了很多空行。您可以创建一个这样的函数,如下所示(来自上面的链接):
os.system()
答案 3 :(得分:0)
你可以使用一堆print()行来过去。
player1move=input()
print("\n"*100)
player2move=input()
print("\n"*100)
#calculate who won
#print result
答案 4 :(得分:0)
这是一个对我没有任何问题的示例
import getpass
user = input('User: ')
password = getpass.getpass('Password: ')
password_lenght = len(password)
password_hide = ('*' * password_lenght)
print(f'{user}, your password {password_hide} is {password_lenght} digits long')