如何在Pygame上显示玩家的得分?

时间:2013-01-20 06:33:25

标签: python memory

我是一名新的程序员从事计算机科学总结的记忆游戏。游戏是这样的:计算机在随机位置显示随机框,然后用户必须猜测框的位置并点击它。

我基本上已经完成了,除了现在我正在尝试创建5个不同级别的难度级别。例如,1级将显示2个框,2级将显示5,等等。然后,如果用户通过所有级别,则可以再次播放。我知道很多,但我真的想得到一个A。

但是现在我被卡住了,因为在我试图关闭窗户之前它并没有真正起作用,即便如此,它只会中途停止。任何帮助将不胜感激。

import pygame , sys
import random
import time
size=[500,500]
pygame.init()
screen=pygame.display.set_mode(size)

# Colours
LIME = (0,255,0) 
RED = (255, 0, 0)
BLACK = (0,0,0)
PINK = (255,102,178)
SALMON = (255,192,203)
WHITE = (255,255,255)
LIGHT_PINK = (255, 181, 197)
SKY_BLUE = (176, 226, 255)
screen.fill(BLACK)

# Width and Height of game box
width=50
height=50

# Margin between each cell
margin = 5

rows = 20
columns = 20


# Set title of screen
pygame.display.set_caption("Spatial Recall")

# Used to manage how fast the screen updates
clock=pygame.time.Clock()


coord=[]

# Create a 2 dimensional array. A two dimesional
# array is simply a list of lists.
def resetGrid():
    grid = []
    for row in range(rows):
        # Add an empty array that will hold each cell
        # in this row
        grid.append([])
        for column in range(columns):
            grid[row].append(0) # Append a cell  
    return grid

def displayAllPink(pygame):
    for row in range(rows):
        for column in range(columns):
            color = LIGHT_PINK
            pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
            pygame.display.flip()      

def displayOtherColor(pygame,grid):
    coord = []
    for i in range(random.randint(2,5)):
        x = random.randint(2, rows-1)
        y = random.randint(2, columns-1)                
        color = LIME    
        pygame.draw.rect(screen,color,[(margin+width)*y + margin,(margin+height)*x+margin,width,height])
        coord.append((x,y))  
        grid[x][y] = 1
        pygame.display.flip() 
    time.sleep(1)
    return coord

def runGame(gameCount,coord,pygame,grid):
    pygame.event.clear()
    pygame.display.set_caption("Spatial Recall: Level "+ str(gameCount))
    pygame.time.set_timer(pygame.USEREVENT,1000)
    time = 0
    #clock.tick( 
            # -------- Main Program Loop -----------
    #Loop until the user clicks the close button.
    done = False
    while done==False:    
        event = pygame.event.wait() # User did something
        if event.type == pygame.QUIT: # If user clicked close
            done=True # Flag that we are done so we exit this loop
            pygame.event.clear()
            print "Game ",gameCount, "ends"
        elif event.type == pygame.USEREVENT:
            time = time + 1
            pygame.display.set_caption("Spatial Recall: Level "+ str(gameCount) + " Time: "+ str(time))
            if time == 100:
                done = True
                pygame.display.set_caption("Time out, moving to next level")
                pygame.event.clear()
                return False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # User clicks the mouse. Get the position
            pos = pygame.mouse.get_pos()
            # Change the x/y screen coordinates to grid coordinates
            column=pos[0] // (width+margin)
            row=pos[1] // (height+margin)
            if (row,column) in coord:
                print coord
                coord.remove((row,column))
                print coord
                color = LIME
                pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
                if coord == []:
                    done=True 
                    pygame.display.set_caption("Time out, moving to next level")
                    pygame.event.clear()
                    return True
            else:
                color = RED
                pygame.draw.rect(screen,color,[(margin+width)*column + margin,(margin+height)*row+margin,width,height])
            pygame.display.flip() 


def startTheGame(gameCount):
    grid = resetGrid()
    displayAllPink(pygame)
    coord = displayOtherColor(pygame,grid)
    displayAllPink(pygame)
    runGame(gameCount,coord,pygame,grid)

for i in range(2):
    startTheGame(i+1)
pygame.quit ()

1 个答案:

答案 0 :(得分:0)

您可能想要使用pygame.font模块。 http://pygame.org/docs/ref/font.html

  • 首先,从文件或其中一个系统字体函数加载字体。
  • 致电YourFontObject.render(your_text_string)。那将返回一个Surface,其中包含以给定字体呈现的字符串。注意,您不能使用换行符(\n)!你必须自己做间距。
  • 在其他所有内容之后将此Surface blit到屏幕上,这样就不会有任何模糊处理。

此外,您的功能中不需要pygame参数。

希望这有帮助。