Question

好吧所以我有一个代码可以将大笔资金变成更小的钱，如：

#!/usr/bin/python3

money = int(input("input your money "))
m1 = 0
t5 = 0
t10 = 0

# split biggger money into smaller one
while money >= 10:
    money = money - 10000
    m10 = m10 + 1
while money >= 5:
    money = money - 5000
    m5 = m5 + 1
while money >= 1:
    money = money - 1000
    m1 = m1 + 1

# print them out
if m10$ > 0:
    print("there are %i 10$" % t10k)
if m5$ > 0:
    print("there are %i 5$" % t5k)
if m1$ > 0:
    print("there are %i 1$" % t1k)

所以无论如何都要缩短这段代码

Answer 1

is there anyway make [the code from the question shorter?]
甚至更正（从perl转换不完整？）
对于denominations一系列以1结尾的自然数，以下内容应该有效;合理的，如果价值下降：

#!/usr/bin/python3

money = int(input("input the amount "))
denominations = (100, 30, 10, 3, 1)

for denomination in denominations:
    count, money = divmod(money, denomination)
    if count:
        print("there are", count, denomination, "radolls")

python将大笔钱换成小钱

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