(
"userServiceIds": "1,2,3",
"enggServiceIds": "4,5,6,2,1",
)
正如在这些数组中,我们只需要enggServiceIds
只在userServiceIds
正如我所要求的结果是: - 仅4,5,6
代码必须在PHP中运行
我试过这段代码
$input = array("$data[userServiceIds]" , "$data[enggServiceIds]");
$result = implode(',',$input);
$str = implode(',',array_unique(explode(',', $result)));
但结果是: - 1,2,3,4,5,6
正如我所要求的结果是: - 仅4,5,6
答案 0 :(得分:2)
由于输入是JSON,首先将其转换为数组。然后使用array_diff
$json = '{
"userServiceIds": "1,2,3",
"enggServiceIds": "4,5,6,2,1"
}';
$aData = json_decode($json, true);
$aResult = array_diff(explode(',',$aData['enggServiceIds']), explode(',',$aData['userServiceIds']));
print_r($aResult);
答案 1 :(得分:1)
$userServiceIds = [1,2,3];
$enggServiceIds = [4,5,6,2,1];
var_dump(array_diff($enggServiceIds, $userServiceIds));
返回:
array(3) {
[0]=>
int(4)
[1]=>
int(5)
[2]=>
int(6)
}
答案 2 :(得分:1)
溶液:
$array1 = array(1,2,3);
$array2 = array(3,4,5,6);
$resultarray = array();
$resultarray = array_diff($array2, $array1);
结果:
Array ( [1] => 4 [2] => 5 [3] => 6 )