我正在使用以下代码来安排部分中的联系人数组(例如,使用前缀&#34联系; A"应显示在" A"部分下)。如果有4-5个触点,那么处理需要20秒。
请问这里有什么问题吗?或任何替代。
let finalArr = NSMutableArray()
for contactDetail in conatctsArr {
let name = (contactDetail as! Dictionary)["givenName"] ?? ""// Getting First character of name
var key = String()
if name.characters.count > 0 {
let index1 = name.index((name.startIndex), offsetBy: 1)
key = name.substring(to: index1)
}
else {
key = ""
}
// getting all contatcts starting with particular character
let predicate=NSPredicate(format: "SELF.givenName beginswith[c] %@",key)
let filteredArr = (conatctsArr as NSArray).filtered(using: predicate)
var dic = Dictionary<String, Any>()
dic["key"] = key
dic["values"] = filteredArr
if filteredArr.count > 0 && !(finalArr.contains(dic)) {
finalArr.add(dic)
}
}
答案 0 :(得分:1)
在每个循环中处理后从数组中删除已过滤的元素可能会提高性能。尝试:
let finalArr = NSMutableArray()
var processingArray = NSMutableArray(array:conatctsArr)
while processingArray.count > 0 {
let contactDetail = processingArray[0]
let name = (contactDetail as! Dictionary)["givenName"] ?? ""
var key = String()
if name.characters.count > 0 {
let index1 = name.index((name.startIndex), offsetBy: 1)
key = name.substring(to: index1)
}
else {
key = ""
}
let predicate=NSPredicate(format: "SELF.givenName beginswith[c] %@",key)
let filteredArr = processingArray.filtered(using: predicate)
if filteredArr.count > 0 {
var dic = Dictionary<String, Any>()
dic["key"] = key
dic["values"] = filteredArr
finalArr.add(dic)
}
processingArray.removeObjects(in: filteredArr)
}
答案 1 :(得分:1)
在您的代码中,对同一个密钥进行多次过滤。试试:
let finalArr = NSMutableArray()
for contactDetail in conatctsArr
{
let keysArray = [“A”, “B”, “C”,…. “Z”]
for key in keysArray
{
let predicate=NSPredicate(format: "SELF.givenName beginswith[c] %@",key)
let filteredArr = (conatctsArr as NSArray).filtered(using: predicate)
var dic = Dictionary<String, Any>()
dic["key"] = key
dic["values"] = filteredArr
if filteredArr.count > 0) {
finalArr.add(dic)
}
}
}