Question

我的代码中出现此语法错误，我无法确定它是否为缩进错误或其他内容（https://i.stack.imgur.com/Alazd.png）。

# Creating a program that gives us the name,score and grade with variation in score and grade! A
name = input("Enter namez")
# print("name:", name)
print()

score = input("Enter scorez")
# print("score:", score)

score = int(score)
if score >= 75:
    grade = 'Excellent'
elif score >= 60:
    grade = 'Very good'
elif score >= 50
    grade = 'Quite good'
elif score >= 40
    grade = 'Not Bad'
elif score >= 30
    grade = 'Pretty Bad'
elif score >= 20
    grade = 'Horibble'
else: grade = 'Appauling'
print()

print('name:', name, 'score:', score, ' and grade:', grade)
print()

print('So,', name, 'you got a score of', score, 'and hence culminates that your grade becomes', grade, '.')

Answer 1

您错过了＆＃34;：＆＃34;在elif条件下和最后四个条件中，将缩进设置为4个空格。

Answer 2

您在semi-colons (:)条件下缺少elif。然后，在grade的最后3次分配中，缩进也不正确。

Answer 3

使用适当的缩进来标记代码块。

您的elif语句缺少冒号。

http://www.python.org/dev/peps/pep-0008/#other-recommendations

始终围绕这些二元运算符，两边都有一个空格：赋值（=），扩充赋值（+ =， - =等），比较（==，＆lt;，＆gt;，！=，＆lt;＆gt; ;，＆lt; =，＆gt; =，in，not in，is，is not），布尔（和，或者，不是）。

例外情况是=用于设置命名参数。

也就是说，您可以将代码转换为可重用的函数。

def grade(score):
    """ Return a grade based on score."""

    rank = ''

    if score >= 75:
        rank = 'Excellent'
    elif score >= 60:
        rank = 'Very good'
    elif score >= 50:
        rank = 'Quite good'
    elif score >= 40:
        rank = 'Not bad'
    elif score >= 30:
        rank = 'Pretty bad'
    elif score >= 20:
        rank = 'Horrible'
    else:
        rank = 'Appalling'

    return rank

name = input('Enter name: ')
score = int(input('Enter score: '))    
report_card = {'Name': name, 'Score': score, 'Grade': grade(score)}

print(report_card)

试运行：

Enter name: X
Enter score: 90
{'Name': 'X', 'Score': 90, 'Grade': 'Excellent'}

语法错误python＆＃39; if＆＃39;和＆＃39;其他＆＃39;声明

3 个答案: