if / else语句中的语法无效导致语法错误

Question

// Check if the user is ready to play!

confirm("Are you ready to play?");

var age = prompt("What's your age");

if ( age is less than 13)
{
    console.log("You are allowed to play,but we take no responsibility");
}

else {
console.log("Go on! you can play");
} 

执行此JavaScript代码时出现语法错误，前两行（确认和变量）正确，此错误位于if / else语句中。

Answer 1

使用<运算符代替is less than

＆＃13;

＆＃13;

// Check if the user is ready to play!

confirm("Are you ready to play?");

var age = prompt("What's your age");
if (age < 13) {
  alert("You are allowed to play, but we take no responsibility");
} else {
  alert("Go on! you can play");
}

＆＃13;

＆＃13;

＆＃13;

Answer 2

您也可以使用三元运算符

来减少代码行数

 age < 13 ?  console.log("You are allowed to play, but we take no      responsibility"):console.log("Go on! you can play");