有人可以帮我解决这个问题,这是我的mongoose聚合代码:
export class GetVehiclesbyKotaCommandHandler {
constructor(namaKota) {
return new Promise((resolve, reject) => {
VehiclesDB.find().populate({
path: 'mitraId',
model: 'RentalDB',
select: 'namaKota'
}).aggregate([
{
$match : {
namaKota:namaKota
}
}
]).lean().then((dataVehicles)=>{
if(dataVehicles !== null){
resolve(dataVehicles);
} else {
reject (new NotFoundException('Couldn\'t find any Vehicles with namaKota' + namaKota));
}
}).catch((errDataVehicles)=>{
reject(new CanNotGetVehiclesException(errDataVehicles.message));
});
});
}}
我在控制台上收到这样的错误:
TypeError: _VehiclesDB2.default.find(...).populate(...).aggregate is not a function
完成,我感谢Hana :) 我改变了我的mitraId类型ObjectId mitraId:{ type:Schema.Types.ObjectId, 要求:是的 },
答案 0 :(得分:0)
您可以在聚合语句中使用$lookup
,而不是在此使用find
和populate
。
像这样:
VehiclesDB.aggregate([
{
$lookup: {
from: 'RentalDB',
localField: 'mitraId',
foreignField: '_id',
as: 'mitra'
}
}, {
$unwind: "$mitra"
}, {
$match: {
"mitra.namaKota": namaKota
}
}
])
我希望这会有所帮助。
答案 1 :(得分:0)
尽量避免查找,填充,精简功能,如下所示
export class GetVehiclesbyKotaCommandHandler {
constructor(namaKota) {
return new Promise((resolve, reject) => {
VehiclesDB.aggregate([
{
$lookup: {
from: 'RentalDB',
localField: 'mitraId',
foreignField: '_id',
as: 'mitra'
}
}, {
$unwind: "$mitra"
}, {
$match: {
"mitra.namaKota": namaKota
}
}
]).then((dataVehicles)=>{
if(dataVehicles !== null){
resolve(dataVehicles);
} else {
reject (new NotFoundException('Couldn\'t find any Vehicles with namaKota' + namaKota));
}
}).catch((errDataVehicles)=>{
reject(new CanNotGetVehiclesException(errDataVehicles.message));
});
});
}}