Question

我正在尝试将用户信息插入MySQL。我创建了以下ajax调用，似乎是在JSON中创建数据，但是当我运行print_r( json_encode( $_GET));时，它显示一个空数组。

在调试器中，似乎调用包含url中的数据：

results.php?method=submitScore&score=1&username=bob

main.html中

function getData(obj,callback){
    $.ajax({
        url: 'results.php',
        type: "GET",
        dataType: "json",
        data: obj
    }).done(function(data) {
        if(callback != null)
            callback(data);
    });
}

results.php

<?php

class Results {
    public $data;
    public $success = true;
    public $errorMessage;
}
 print_r( json_encode( $_GET));

$func = $_GET['method'];
$obj = new Results();



switch ($func) {

        case "getHighScores":
        $conn = new  mysqli('localhost','Username','Password','DB');
        if (!$conn->connect_errno) {
            $high = "SELECT * FROM HighScores ORDER BY Score LIMIT 10";
            $scores = $conn->query($high);
            $arr = array();
            while ($row = $scores->fetch_assoc()){
                $arr[] = $row;
            }
            $obj->data = $arr;
            echo json_encode($obj);
        }
        break;
    case "submitScore":
        $userName = $_GET["username"];
        $score = $_GET["score"];
        $conn = new  mysqli('localhost','W01214804','Kylecs!','W01214804');
        if (!$conn->connect_errno) {
            $query = "INSERT INTO HIGHSCORES VALUES('" . $userName . "', '" . $score . "')";
            $conn->query($query);
    }
        break;
    default:
        echo "Invalid method";
        break;







    }

?>

PHP没有从Ajax Json Call接收数据

0 个答案: