Question

我一直在寻找答案。

我有JSON字符串

"[{"id":"0"}]"

我试过

obj['id'] and obj.id

但这不起作用

    $.ajax({
        url: 'php/checkdoctorappointmentonday.php',
        data: 'doctorName=' + doctorName + '&dayOfEvent=' + date1,
        type: "POST",
        success: function (json) {
            obj = JSON.parse(json.data)[0];
            b = obj.id;
        }
    });
    return true;
}

我错过了什么吗？

这是用于获取结果的php 修改

    <?php
$doctorName = $_POST['doctorName'];
$dayOfEvent = $_POST['dayOfEvent'];


// Query that retrieves events
$query = "SELECT COUNT(id) AS 'id'
            FROM doctoravailability
            WHERE start >='$dayOfEvent' AND start < DATE_ADD('$dayOfEvent', INTERVAL 1 DAY)
            AND title = '$doctorName'
            AND backgroundColor = 'red'
          ";

// connection to the database
try {
    $bdd = new PDO("mysql:host=$servername;dbname=$dbname",$username,$password);
} catch(Exception $e) {
    exit('Unable to connect to database.');
}
// Execute the query
$resultat = $bdd->query($query) or die(print_r($bdd->errorInfo()));

// sending the encoded result to success page
echo json_encode($resultat->fetchAll(PDO::FETCH_ASSOC));

?>

Answer 1

你的JSON字符串实际上是否有开头和结尾＆＃34;在其中，或者你刚刚在那里添加它们来说明它是一个字符串？

假设我们的数据字符串实际上有＆＃34;，那么您只想使用语法

[{"id":"0"}]

Answer 2

根据评论，该对象实际上是一个包含对象的数组

var str = "[{\"id\":\"0\"}]";
var obj = JSON.parse(str)[0];
alert(obj.id);

http://jsfiddle.net/6ae0bgag/

obj [＆＃34; id＆＃34;]也会有效，与obj.id相同

Answer 3

试试这个：

<强> JS

$.ajax({
        url: 'php/checkdoctorappointmentonday.php',
        data: {
            doctorName: doctorName,
            dayOfEvent: date1
        },      
        type: "POST",
        dataType: 'json',
        success: function (data) {
            console.log(data);
            b = data.0.id;
        }
    });

<强> PHP

<?php
    $doctorName = $_POST['doctorName'];
    $dayOfEvent = $_POST['dayOfEvent'];


    // Query that retrieves events
    $query = "SELECT COUNT(id) AS 'id'
                FROM doctoravailability
                WHERE start >='$dayOfEvent' AND start < DATE_ADD('$dayOfEvent', INTERVAL 1 DAY)
                AND title = '$doctorName'
                AND backgroundColor = 'red'
              ";

    // connection to the database
    try {
        $bdd = new PDO("mysql:host=$servername;dbname=$dbname",$username,$password);
    } catch(Exception $e) {
        exit('Unable to connect to database.');
    }
    // Execute the query
    $resultat = $bdd->query($query) or die(print_r($bdd->errorInfo()));

    // sending the encoded result to success page
    return $resultat->fetchAll(PDO::FETCH_ASSOC);
?>

从ajax调用中获取JSON.parse中的数据

3 个答案: