我一直在试图解决这个问题,我已经阅读了很多博客并尝试了不同的东西,但我仍然遇到同样的错误,而且我不明白我的代码有什么问题。我我试图将几个csv文件同时拉入R并且我不断收到以下错误。
文件中没有此类文件或directoryError(文件," rt"):无法打开连接
`Tea_ONE <- "~/Desktop/Circadian Rhythms
Sem/Project/Tea_Party_ONE/Tea_Party_ONE_Lumicycle_data/"
files <- list.files(path = Tea_ONE, pattern = ".csv$")
for(i in 1:length(files)){
assign(files[i],
read.csv(paste(Tea_ONE, files[i], header = T, skip = 1)))
}`
所有CSV文件都位于Tea_Party_ONE_Lumicycle_data中。
感谢您的帮助
答案 0 :(得分:2)
正如评论中提到的,问题是paste0
正在添加空格分隔符。您可以使用library('tidyverse')
files <- list.files(path = Tea_ONE, pattern = '.csv$', full.names = T) %>%
map(read_csv, skip = 1)
,也可以获取完整路径名称。
push
答案 1 :(得分:2)
有很多方法!!
setwd("C:/your_path_here")
fnames <- list.files()
csv <- lapply(fnames, read.csv)
result <- do.call(rbind, csv)
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filedir <- setwd("C:/your_path_here")
file_names <- dir(filedir)
your_data_frame <- do.call(rbind,lapply(file_names,read.csv))
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filedir <- setwd("C:/your_path_here")
file_names <- dir(filedir)
your_data_frame <- do.call(rbind, lapply(file_names, read.csv, skip = 1, header = FALSE))
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filedir <- setwd("C:/your_path_here")
file_names <- dir(filedir)
your_data_frame <- do.call(rbind, lapply(file_names, read.csv, header = FALSE))
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#
temp <- setwd("C:/your_path_here")
temp = list.files(pattern="*.csv")
myfiles = lapply(temp, read.delim)
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# Here is another options to convert the .csv files into one data.frame. Using R base functions.
# This is order of magnitude slower than the options below.
files <- setwd("C:/your_path_here")
# Get the files names
files = list.files(pattern="*.csv")
# First apply read.csv, then rbind
myfiles = do.call(rbind, lapply(files, function(x) read.csv(x, stringsAsFactors = FALSE)))
library(readr)
library(dplyr)
tbl = lapply(files, read_csv) %>% bind_rows()
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# LIST OF FILE PATHS
library(readr)
library(stringr)
List_of_file_paths <- list.files(path ="C:/your_path_here/", pattern = ".csv", all.files = TRUE, full.names = TRUE)
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# LIST OF FILES IN FOLDER
xlist<-list.files(pattern = "*.csv")
for(i in xlist) {
x <- read.csv((i))
assign(i, x)
}
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