Question

我已经尝试了很多东西并不断更改此代码，但我无法在接受“得分”值之前停止需要两个输入。此外，我一直无法找到一种方法来阻止cin从“得分”中得分。并且回答＆＃39; 允许用户在不输入值的情况下按Enter键。我认为这样做的唯一方法就是接受它们作为字符串，但我希望避免这种情况。

＆＃13;

#include<iostream>
#include<iomanip>
#include<limits>**strong text**

using namespace std;

//void enterdata(string*, int*);

int main(){
//	string names[];
//	int testscores[];
	string name;
	int score;
	char answer;

	cout<<"This program asks the user to enter a list of names and test scores,"<<endl;
	cout<<"then sorts the list into ascending order according to the scores"<<endl;
	cout<<"and calculates the average test score."<<endl;

//	enterdata(names, testscores);

	do{
			cout<<"Please enter a name: ";
			getline(cin, name);
			while(name.empty()){
				cout<<"No entry detected. Please enter a name: ";
				getline(cin, name);
			}
			cout<<name<<endl;
			cout<<"Please enter a test score: ";
			cin>>score;
			while(!(cin>>score) || score<0){
				cin.clear();
			    cin.ignore(numeric_limits<streamsize>::max(), '\n');
			    cout<<"Input not valid. Only positive integers will be accpeted."<<endl;
			    cout<<"Please enter a test score: ";
			}
			cout<<score<<endl;
			cin.sync();
			cout<<"Would you like to enter another student name and test score? [y/n] ";
			cin>>answer;
			while(answer!='y' && answer!='n'){
			    cout<<"Input not valid. Only y or n will be accepted."<<endl;
			    cout<<"Would you like to enter another student name and test score? [y/n] ";
			    cin>>answer;
			}
			cout<<answer<<endl;
			cin.sync();
		} while(answer == 'y');

	return 0;
}

＆＃13;

Answer 1

错误在于：

while(!(cin>>score) || score<0){ //------ Here!
    cin.clear();
    cin.ignore(numeric_limits<streamsize>::max(), '\n');
    cout<<"Input not valid. Only positive integers will be accpeted."<<endl;
    cout<<"Please enter a test score: ";
}

当您说cin>>score时，您正在再次使用输入流，因此程序会提示输入更多内容！将其视为函数调用（提示：运算符重载！）。我认为你写了这个（即!(cin>>score），因为你想测试流的错误。在这样的小型项目中，我不会出汗（学校运动？）

关于你提出问题的第二部分，关于妨碍进入效果（烦人的换行），我很确定你不能轻易做到这一点。我礼貌地问你是否真的想花时间在这上面（如果是学校练习，其他人都会有同样的问题）

以下是经过清理和更正的代码：

#include <iostream>
#include <iomanip>
#include <limits>
#include <string>

using std::cout;
using std::cin;
using std::string;
using std::endl;

//void enterdata(string*, int*);

int main() {
  //string names[];
  //int testscores[];
  string name;
  int score;
  char answer = 'y';

  cout << "This program asks the user to enter a list of names and test scores," << endl;
  cout << "then sorts the list into ascending order according to the scores" << endl;
  cout << "and calculates the average test score." << endl;

  //enterdata(names, testscores);

  while(answer == 'y') {
    cout << "Please enter a name: ";
    std::cin >> name;
    while (name.empty()) {
        cout << "No entry detected. Please enter a name: ";
        std::cin >> name;
    }
    cout << name << endl;
    cout << "Please enter a test score: ";
    cin >> score;
    while (score<0) {
        cin >> score;
        cin.clear();
        cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
        cout << "Input not valid. Only positive integers will be accpeted." << endl;
        cout << "Please enter a test score: ";
    }
    cout << score << endl;
    cin.sync();
    cout << "Would you like to enter another student name and test score? [y/n] ";
    cin >> answer;
    while (answer != 'y' && answer != 'n') {
        cout << "Input not valid. Only y or n will be accepted." << endl;
        cout << "Would you like to enter another student name and test score? [y/n] ";
        cin >> answer;
    }
    cout << answer << endl;
    cin.sync();
 } 
return 0;
}

C ++ cin在接受值之前需要2个或更多输入

1 个答案: