Question

我的作业要求输出类似于：

示例输出：输入产品类型和销售数量（输入Z停止）：A 2

产品A的总销售额= $ 5.97

字母代表对象的价格，后面的数字代表对象的数量。那么我如何得到我的cin以获得对象和数量？我目前有：

#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;

int main()
{ 
    double ProfitA, ProfitB, ProfitC;
    double TotalA = 0;
    char type;
    int quant; 
    ProfitA = (1.99) * quant;
    ProfitB = (2.99) * quant;
    ProfitC = (3.99) * quant;

    cout << "Enter product type and quantity sold (enter -1 to stop)\n\n";
    cin >> type >> quant;
    switch (type)
    {
    case 'A':cout << "Total sales of product A =" << ProfitA << "\n";
        break;
    case 'B':cout << "Total sales of product B =" << ProfitB << "\n";
        break;
    case 'C':cout << "Total sales of product C =" << ProfitC << "\n";
        break;
    }

Answer 1

运行程序时，在每次输入后输入enter。然后在运行程序之前，编辑代码以在输入之后进行利润计算

Answer 2

正如@Pete Becker指出的那样，您试图在用户输入数量之前计算利润。

将您的代码更改为：

char type;
int quant; 

cout << "Enter product type and quantity sold (enter -1 to stop)\n\n";
cin >> type >> quant;

ProfitA = (1.99) * quant;
ProfitB = (2.99) * quant;
ProfitC = (3.99) * quant;

一个＆＃34; cin＆＃34;

2 个答案: