根据在两列上完成的计算，返回MAX值的所有行

Question

我有一张名为＆＃39; Houses＆＃39;其中包含字段＆＃39; house_id＆＃39;，＆＃39; house_type＆＃39;，＆＃39; bhk_detail＆＃39;，＆＃39; bed_count＆＃39;，＆＃39; furnishing_type＆＃39;，＆＃ 39; Beds_vacant＆＃39 ;.现在我需要写一个查询，以获得最高入住率的房子的房子细节bed_count - bed_vacant。我试过这样的事情：

SELECT hs.house_id, hs.house_type , hs.bhk_details, hs.bed_count , hs.furnishing_type, hs.Beds_vacant,
       max(hs.bed_count - hs.Beds_vacant
FROM Houses as hs 
GROUP BY hs.house_id, hs.house_type, hs.bhk_details, hs.bed_count, hs.furnishing_type, hs.Beds_vacant 
HAVING MAX(hs.bed_count - hs.Beds_vacant)IN (SELECT max(hs.bed_count - hs.Beds_vacant) FROM Houses as hs) 

该查询对我有用，但我想知道我们是否可以更精确地编写

Answer 1

我认为最简单的方法是top 1 with ties：

select top (1) with ties h.*
from Houses h
order by (h.bed_count - h.beds_vacant) desc;