从用户输入动态填充数组时接收非零退出状态

Question

#include <stdio.h>


  int main(void){

    int inputNumber;
    int counter=0;
    int totalValue;
    int arr[counter];
    int avg;

    puts("Please enter any number of positive whole numbers you would like to be averaged. Enter ' -1 ' when you are finished for your result.\n");

    while(scanf("%d\n", &arr[counter])){

      if(arr[counter] = -1){

        break;
      }
      if(arr[counter] > 0){

        totalValue += arr[counter];
        ++counter;

      }
      else if(arr[counter]<=0){

        puts("Please enter a positive number.");

      }
      else{

      }

    } 

    avg = totalValue/counter;
    printf("The average of your entered values is: %d", avg);
    return 0;
  }

我尝试过很多东西试图阻止它，虽然这可能来自缺乏知识，除了创建一个巨大的数组之外，还有什么方法可以做到这一点吗？

我尝试使用带有calloc（）的动态数组，但我遇到了同样的错误。我不确定此方法中还有哪些可用选项。

代码应该取平均值＆＃34; n＆＃34;用户输入的值。

Answer 1

您不需要阵列。

快速＆amp;你想做的很脏但更容易

    int     number = 0;
    int     counter = 0;    
    int     total = 0;

    while (number != -1)
    {
        total += number;
        ++counter;
        scanf("%d", &number);
    }

    printf("average = %d\n", total / (counter - 1) );