Question

这个自相矛盾的错误是什么意思？

subprocess.CalledProcessError：Command＆＃39; / home / travis / build / fritzo / pomagma / build / debug / src / cartographer / cartographer＆＃39;返回非零退出状态0

当我启动一个子进程，然后告诉该子进程通过zmq套接字干净地退出时，就会发生这种情况。看来，当zmq进行轮询时，进程干净地退出（退出代码0），然后引发此错误。

这里是整个追溯（来自travis log）：

Traceback (most recent call last):
  File "/home/travis/virtualenv/python2.7_with_system_site_packages/bin/pomagma.make", line 9, in <module>
    load_entry_point('pomagma==0.2.8', 'console_scripts', 'pomagma.make')()
  File "/home/travis/virtualenv/python2.7_with_system_site_packages/local/lib/python2.7/site-packages/parsable.py", line 181, in dispatch
    dispatch(argv)
  File "/home/travis/virtualenv/python2.7_with_system_site_packages/local/lib/python2.7/site-packages/parsable.py", line 129, in dispatch
    parser(*args, **kwargs)
  File "/home/travis/virtualenv/python2.7_with_system_site_packages/local/lib/python2.7/site-packages/parsable.py", line 64, in parser
    fun(*typed_args, **typed_kwargs)
  File "/home/travis/build/fritzo/pomagma/pomagma/make.py", line 130, in test_atlas
    _test_atlas(theory)
  File "/home/travis/build/fritzo/pomagma/pomagma/make.py", line 59, in _test_atlas
    assert actual_size == expected_size
  File "/usr/lib/python2.7/contextlib.py", line 24, in __exit__
    self.gen.next()
  File "/home/travis/build/fritzo/pomagma/pomagma/cartographer/__init__.py", line 14, in load
    client.stop()
  File "/home/travis/build/fritzo/pomagma/pomagma/cartographer/client.py", line 207, in stop
    self._call(request)
  File "/home/travis/build/fritzo/pomagma/pomagma/cartographer/client.py", line 35, in _call
    self._poll_callback()
  File "/home/travis/build/fritzo/pomagma/pomagma/cartographer/server.py", line 66, in check
    self.log_error()
  File "/home/travis/build/fritzo/pomagma/pomagma/cartographer/server.py", line 73, in log_error
    raise CalledProcessError(self._proc.poll(), BINARY)
subprocess.CalledProcessError: Command '/home/travis/build/fritzo/pomagma/build/debug/src/cartographer/cartographer' returned non-zero exit status 0

Answer 1

根据文档，如果您的子进程返回非零，那么它将引发该异常。这也是Linux中的标准约定。 https://docs.python.org/2/library/subprocess.html

尝试包含您的子流程客户端代码尝试：＆LT; ...＆GT; 抓住：＆LT; ...＆GT; 最后： sys.exit（0）

subprocess.CalledProcessError：返回非零退出状态0

1 个答案: