Question

我有以下数组：

var Set = ("BENELUX,Luxembourg,PP3a,Western_Europe,France,PP6a").split(',');

按顺序工作，我想一次取三个元素并将每个元素分配给一个变量。我想要的结果是：

var Aggreg = ["BENELUX", "Western Europe"]
var Country = ["Luxembourg", "France"] 
var Product = ["PP3a", "PP6a"]

'Set'中元素的顺序始终是顺序的，并且总是3的倍数。我确信这是一种聪明有效的方法。有人能指出我正确的方向吗？

Answer 1

您可以使用解构赋值，增量变量来反映索引

＆＃13;

var set = "BENELUX,Luxembourg,PP3a,Western_Europe,France,PP6a".split(",");

var n = 0, m = 3;

var fn = (arr, a = 0, b = 3) => [arr[a], arr[b]];

var [Aggreg, Country, Product] = [
  fn(set),
  fn(set, ++n, ++m),
  fn(set, ++n, ++m)
];

console.log(Aggreg, Country, Product);

＆＃13;

替代地

＆＃13;

var set = "BENELUX,Luxembourg,PP3a,Western_Europe,France,PP6a".split(",");

var fn = function* (arr) {
  var n = 0, m = 3;
  while (m < arr.length) {
    yield [arr[n], arr[m]];
    n += 1; m += 1;
  }
};

var [Aggreg, Country, Product] = fn(set);

console.log(Aggreg, Country, Product);

＆＃13;

Answer 2

只需使用模数过滤您的数组（如果您确定数据 - 在这种情况下，请确保获得3个数组大小的倍数）：

＆＃13;

const data = "BENELUX,Luxembourg,PP3a,Western_Europe,France,PP6a".split(",")

function extract(data, shift) {
  return data.filter((value, index) => (index % 3) === shift)
}

const Aggreg = extract(data, 0)
const Country = extract(data, 1)
const Product = extract(data, 2)

console.log(Aggreg, Country, Product)

＆＃13;

Answer 3

您可以使用.reduce()将每个部分放入单个对象内的数组中，然后使用解构赋值来分配单个变量，如下所示：

＆＃13;

var Set = ("BENELUX,Luxembourg,PP3a,Western_Europe,France,PP6a").split(',');

var {Aggreg, Country, Product} = Set.reduce(function (result, curr, index) {
  if (index % 3 === 0) {
    result.Aggreg.push(curr);
  }
  else if (index % 3 === 1) {
    result.Country.push(curr);
  }
  else {
    result.Product.push(curr);
  }
  return result;
}, {Aggreg: [], Country: [], Product: []})

console.log(Aggreg);
console.log(Country);
console.log(Product);

＆＃13;

Answer 4

可以使用简单的for(reset($broken);$kv = myEach($broken);) {...}：

Array.prototype.forEach()

在jquery中的3个变量中分配数组元素

4 个答案: