Question

我希望有一个过程，它接受3个employee_id作为参数然后比较它们，最低和最高将被交换，而中间的一个被留下。我不确定我是否正确接近这个，我在if else部分继续在oracle apex上出错。我读过可能更容易实现案例陈述？ - 注意：这是一个家庭作业问题到目前为止我所拥有的：

create or replace procedure myproc(empid in number, empid in number, empid in number) is
  originalsalary1   employees.salary%type;
  originalsalary2   employees.salary%type;
  originalsalary3   employees.salary%type;
  newsalary         employees.salary%type;
begin
  select salary INTO originalsalary1 from employees
  where employee_id = empid;
  select salary INTO originalsalary2 from employees
  where employee_id = empid;
  select salary INTO originalsalary3 from employees
  where employee_id = empid;
  if originalsalary1 <= originalsalary2 and originalsalary3 then
    newsalary := originalsalary1 * 1.1; 
  elseif originalsalary2 <= originalsalary1 and originalsalary3 then
    newsalary := originalsalary2 * 1.1;
  elseif originalsalary3 <= originalsalary1 and originalsalary2 then
    newsalary := originalsalary3 * 1.1;
  end if;
end;
/

Answer 1

CREATE OR REPLACE PROCEDURE PR_PREP(EMPID1 IN INT, EMPID2 IN INT , EMPID3 IN 
INT)
 IS
 MAX_SAL_EMP_ID INT;
 MIN_SAL_EMP_ID INT;
 MAX_SAL EMPLOYEES.SALARY%TYPE;
 MIN_SAL EMPLOYEES.SALARY%TYPE;
 BEGIN
   SELECT EMP_ID , SALARY INTO MAX_SAL_EMP_ID , MAX_SAL FROM EMPLOYEES WHERE 
    EMP_ID IN (EMPID1, EMPID2, EMPID3)
    AND SALARY = (SELECT MAX(SALARY) FROM EMPLOYEES WHERE EMP_ID IN (EMPID1, 
   EMPID2, EMPID3));

   SELECT EMP_ID , SALARY INTO MIN_SAL_EMP_ID , MIN_SAL FROM EMPLOYEES WHERE 
    EMP_ID IN (EMPID1, EMPID2, EMPID3)
    AND SALARY = (SELECT MIN(SALARY) FROM EMPLOYEES WHERE EMP_ID IN (EMPID1, 
    EMPID2, EMPID3));

    UPDATE EMPLOYEES SET SALARY = MAX_SAL WHERE EMP_ID = MIN_SAL_EMP_ID;
    UPDATE EMPLOYEES SET SALARY = MIN_SAL WHERE EMP_ID = MAX_SAL_EMP_ID;
    COMMIT;
   END;

PL / SQL程序比较3名员工的工资，然后交换最低和最高工资

1 个答案: