Question

注意，这是一个家庭作业问题。

请显示平均工资最高的部门的部门编号和最低工资。

这是我到目前为止所拥有的，

SELECT DEPARTMENT_ID, MAX_AVG_SALARY
FROM
  (SELECT DEPARTMENT_ID, AVG(SALARY) AS MAX_AVG_SALARY
  FROM EMPLOYEES
  GROUP BY DEPARTMENT_ID)
WHERE MAX_AVG_SALARY =
  (SELECT MAX(MAX_AVG_SALARY)
  FROM
    (SELECT DEPARTMENT_ID,
      AVG(SALARY) AS MAX_AVG_SALARY
    FROM EMPLOYEES
    GROUP BY DEPARTMENT_ID
    ));

我可以获得薪水最高的department_id，但是如何找到同一部门的最低工资？

请帮忙！

谢谢！

Answer 1

SELECT MINIMUM_SALARY,DEPARTMENT_ID
FROM
(
 SELECT AVG(SALARY) AS AVERAGE_SALARY,
        MIN(SALARY) AS MINIMUM_SALARY,
        DEPARTMENT_ID
  FROM EMPLOYEES
 GROUP BY DEPARTMENT_ID
)EMPLOYEE_AGGREGATED
WHERE
    AVERAGE_SALARY = (SELECT MAX(AVG(SALARY)) FROM EMPLOYEES GROUP BY DEPARTMENT_ID)

Answer 2

analytic functions的解决方案：

select department_id, ms min_salary 
  from (
    select department_id, max(avg(salary)) over () mav,
        min(min(salary)) over (partition by department_id) ms, 
        min(avg(salary)) over (partition by department_id) av 
      from employees group by department_id )
  where av = mav order by department_id

SQLFiddle demo

Answer 3

您可以使用可以重复使用的命名子查询：

WITH grouped_salaries AS (
  SELECT department_id,
         MIN( salary ) AS min_dept_salary,
         AVG( salary ) AS avg_dept_salary
  FROM   Employees
  GROUP BY department_id
)
SELECT department_id,
       min_dept_salary
FROM   grouped_salaries
WHERE  avg_dept_salary = ( SELECT MAX( avg_dept_salary )
                           FROM   grouped_salaries );

Answer 4

select e.department_id, min(e.salary) min
  from employees e
having avg(e.salary) = (select max(avg(e.salary))
                          from employees e
                         group by e.department_id)
 group by e.department_id

Answer 5

这是不使用行限制功能的答案，因为旧的 oracle 不提供行限制功能

SELECT job_id, avg(salary) FROM Employees 
GROUP BY job_id 
HAVING AVG(salary) = (SELECT MIN(AVG(salary)) FROM EMPLOYEES GROUP BY job_id);

Answer 6

WITH CTE(ID, SAL) AS 
(
   SELECT DISTINCT
      DEPARTMENT_ID,
      AVG(SALARY) OVER(PARTITION BY DEPARTMENT_ID)"AVGSAL" 
   FROM
      EMPLOYEES 
   ORDER BY
      AVGSAL DESC
)
SELECT
   MIN(SALARY) 
FROM
   EMPLOYEES E1 
WHERE
   E1.DEPARTMENT_ID = 
   (
      SELECT
         ID 
      FROM
         CTE 
      WHERE
         ROWNUM = 1
   )
;

ORACLE SQL：显示平均薪水最高的部门的最低工资

6 个答案: