以下工作原理和输出结果如下图所示。
SELECT
SU_Internal_ID,
NQ_QuestionText,
NA_AnswerText,
NoOfTimesChoosen
FROM
(SELECT
U.SU_Internal_ID,
NQ.NQ_QuestionText,
NA.NA_AnswerText,
COUNT(PC.UserID) AS NoOfTimesChoosen
FROM [dbo].[ParticipantNSChoices] PC
INNER JOIN [dbo].[KnowledgeSurveyAnswers] NA
on PC.NA_Internal_ID = NA.NA_Internal_ID
INNER JOIN [dbo].[KnowledgeSurveyQuestions] NQ
on PC.NQ_Internal_ID = NQ.NQ_Internal_ID
INNER JOIN [dbo].[AspNetUsers] U
on PC.UserID = U.Id
WHERE
U.SU_Internal_ID=1
and NQ.NQ_QuestionText LIKE '%Do you feel comfortable working with computers%'
GROUP
BY U.SU_Internal_ID,
NQ.NQ_QuestionText,
NA.NA_AnswerText ) as A
我想添加一列来显示两个答案的百分比'否'并且'是':旁边的'否'我想要' 20'并且旁边是'是' ' 80',但我在这方面很新,而且被卡住了;我将不胜感激任何帮助。感谢。
答案 0 :(得分:0)
你不需要外部的SELECT。
SELECT
U.SU_Internal_ID,
NQ.NQ_QuestionText,
NA.NA_AnswerText,
COUNT(PC.UserID) AS NoOfTimesChoosen,
(cast(COUNT(PC.UserID) as float) /
cast(
(select count(*) from [dbo].[ParticipantNSChoices] PC2
INNER JOIN [dbo].[KnowledgeSurveyAnswers] NA2 on PC2.NA_Internal_ID = NA2.NA_Internal_ID
INNER JOIN [dbo].[KnowledgeSurveyQuestions] NQ2 on PC2.NQ_Internal_ID = NQ2.NQ_Internal_ID
INNER JOIN [dbo].[AspNetUsers] U2 on PC2.UserID = U2.Id
WHERE
U2.SU_Internal_ID=1
and NQ2.NQ_QuestionText LIKE '%Do you feel comfortable working with computers%' )
as float))
* 100 as PercentChosen
FROM [dbo].[ParticipantNSChoices] PC
INNER JOIN [dbo].[KnowledgeSurveyAnswers] NA
on PC.NA_Internal_ID = NA.NA_Internal_ID
INNER JOIN [dbo].[KnowledgeSurveyQuestions] NQ
on PC.NQ_Internal_ID = NQ.NQ_Internal_ID
INNER JOIN [dbo].[AspNetUsers] U
on PC.UserID = U.Id
WHERE
U.SU_Internal_ID=1
and NQ.NQ_QuestionText LIKE '%Do you feel comfortable working with computers%'
GROUP
BY U.SU_Internal_ID,
NQ.NQ_QuestionText,
NA.NA_AnswerText
counts
将为integers
,因此您需要cast
作为floats
才能进行分割。然后,您可以根据自己的喜好进一步格式化。此外,我可能没有您的确切分母,因为我不知道您的数据是什么样的,但您可以修改以匹配您需要的数据。