Question

我有这个丑陋的查询......

sum(CASE 
        WHEN effective_from_date < '2011-05-24' THEN (rate * (effective_to_date - '2011-05-24' + 1)) 
        WHEN effective_to_date > '2011-05-28' THEN (rate * ('2011-05-28' - effective_from_date + 1)) 
        ELSE (rate * (effective_to_date - effective_from_date + 1))
    END
    ) as price_cal_rate
        FROM calendar_event
        WHERE property_rid = (SELECT rid FROM property WHERE web_id = 'T28314') AND 
        ((effective_from_date BETWEEN '2011-05-24' AND '2011-05-28')  OR (effective_to_date BETWEEN '2011-05-24' AND '2011-05-28')) 
         AND 
         NOT EXISTS (

         SELECT days_diff FROM (


        SELECT  ((effective_from_date - lag(effective_to_date) OVER (PARTITION BY NULL ORDER BY effective_from_date ASC))) AS days_diff, effective_from_date, effective_to_date
             FROM calendar_event
             WHERE property_rid = (SELECT rid FROM property WHERE web_id = 'T28314') AND 
        ((effective_from_date BETWEEN '2011-05-26' AND '2011-05-28') OR (effective_to_date BETWEEN '2011-05-26' AND '2011-05-28')) 


        ) AS t WHERE COALESCE(days_diff, 0) > 1 

        ) AND EXISTS (select * from  (
          select min(effective_from_date) as min_date, max(effective_to_date) as max_date FROM calendar_event
        WHERE property_rid = (SELECT rid FROM property WHERE web_id = 'T28314') AND 
        ((effective_from_date BETWEEN '2011-05-24' AND '2011-05-28')  OR (effective_to_date BETWEEN '2011-05-24' AND '2011-05-28'))
        ) as max_min WHERE min_date <= '2011-05-24' and max_date >= '2011-05-28')

查询正在计算日期范围内的费率....查询很好......但查询中有很多重复....我想知道是否有一个很好的方法来存储这个子查询在某处的结果

FROM calendar_event
        WHERE property_rid = (SELECT rid FROM property WHERE web_id = 'T28314') 
AND 
            ((effective_from_date BETWEEN '2011-05-24' AND '2011-05-28')  OR (effective_to_date BETWEEN '2011-05-24' AND '2011-05-28'))

并在我的查询中使用它....

Answer 1

您可以使用临时表作为“mu太短”的建议，但如果您只需要单个“主”查询中的结果并且您使用的是PostgreSQL 8.4或更高版本，那么您也可以使用with queries

在子查询中重用查询结果

1 个答案: