Question

嘿，我一直在编码工作4周左右，现在我正在尝试做一个tic toc拖曳游戏。到目前为止，我已经做到了这一点，我可以玩游戏并找到胜利者。当所有9个空格都已满时，我对如何确定绘图有点困惑。

我还需要在找到胜利者时停止游戏。换句话说，当找到胜利者时，不可能再放一块。

如果有人可以提供帮助，那就太棒了！

以下是我确定胜利者的不太友好的代码。

// check rows
        if (GameBoard[0, 0] == 'X' && GameBoard[0, 1] == 'X' && GameBoard[0, 2] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }
        if (GameBoard[1, 0] == 'X' && GameBoard[1, 1] == 'X' && GameBoard[1, 2] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }
        if (GameBoard[2, 0] == 'X' && GameBoard[2, 1] == 'X' && GameBoard[2, 2] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }

        // check columns
        if (GameBoard[0, 0] == 'X' && GameBoard[1, 0] == 'X' && GameBoard[2, 0] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }
        if (GameBoard[0, 1] == 'X' && GameBoard[1, 1] == 'X' && GameBoard[2, 1] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }
        if (GameBoard[0, 2] == 'X' && GameBoard[1, 2] == 'X' && GameBoard[2, 2] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }

        // check diags
        if (GameBoard[0, 0] == 'X' && GameBoard[1, 1] == 'X' && GameBoard[2, 2] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }
        if (GameBoard[0, 2] == 'X' && GameBoard[1, 1] == 'X' && GameBoard[2, 0] == 'X') { message = "Winner winner chicen dinner Player 1 You won! GG"; }





        // check rows
        if (GameBoard[0, 0] == 'O' && GameBoard[0, 1] == 'O' && GameBoard[0, 2] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }
        if (GameBoard[1, 0] == 'O' && GameBoard[1, 1] == 'O' && GameBoard[1, 2] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }
        if (GameBoard[2, 0] == 'O' && GameBoard[2, 1] == 'O' && GameBoard[2, 2] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }

        // check columns
        if (GameBoard[0, 0] == 'O' && GameBoard[1, 0] == 'O' && GameBoard[2, 0] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }
        if (GameBoard[0, 1] == 'O' && GameBoard[1, 1] == 'O' && GameBoard[2, 1] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }
        if (GameBoard[0, 2] == 'O' && GameBoard[1, 2] == 'O' && GameBoard[2, 2] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }

        // check diags
        if (GameBoard[0, 0] == 'O' && GameBoard[1, 1] == 'O' && GameBoard[2, 2] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }
        if (GameBoard[0, 2] == 'O' && GameBoard[1, 1] == 'O' && GameBoard[2, 0] == 'O') { message = "Winner winner chicen dinner Player 2 You won! GG"; }

Answer 1

到目前为止，你做得很好，你似乎缺少的是功能的使用。例如，您可以定义一个函数来检查单行：

import cv2
import sys
import logging as log
import datetime as dt
from time import sleep

cascPath = "haarcascade_frontalface_default.xml"
faceCascade = cv2.CascadeClassifier(cascPath)
log.basicConfig(filename='webcam.log',level=log.INFO)

video_capture = cv2.VideoCapture(0)
anterior = 0

while True:
    if not video_capture.isOpened():
        print('Unable to load camera.')
        sleep(5)
        pass

    # Capture frame-by-frame
    ret, frame = video_capture.read()

    gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)

    faces = faceCascade.detectMultiScale(
        gray,
        scaleFactor=1.1,
        minNeighbors=5,
        minSize=(30, 30)
    )

    # Draw a rectangle around the faces
    for (x, y, w, h) in faces:
        cv2.rectangle(frame, (x, y), (x+w, y+h), (0, 255, 0), 2)

    if anterior != len(faces):
        anterior = len(faces)
        log.info("faces: "+str(len(faces))+" at "+str(dt.datetime.now()))


    # Display the resulting frame
    cv2.imshow('Video', frame)


    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

    # Display the resulting frame
    cv2.imshow('Video', frame)

# When everything is done, release the capture
video_capture.release()
cv2.destroyAllWindows()

然后我们可以创建一个包装函数：

bool SingleRowComplete(int rowNum, char player) {
    return GameBoard[rowNum, 0] == player && GameBoard[rowNum, 1] == player && GameBoard[rowNum, 2] == player;
}

您可以为列和主对角线创建类似的功能。

一旦关闭，请检查然后封装：

bool AnyRowComplete(char player) {
return SingleRowComplete(0, player) || SingleRowComplete(1, player) || SingleRowComplete(2, player);
}

我想作为最后一点，我会说好工作，现在要学习功能:)。

Answer 2

就个人而言，我建议您在需要检查阵列时使用循环。它将使您的代码更清晰，更易于阅读。

现在，对于你的第一个问题：当你的游戏开始时，用一些既不是＆＃39; X＆＃39;也不是＆＃39; O＆＃39; （空字符串也是一个选项）。编写一个函数，在每个回合之后迭代整个数组并查找该初始化值。如果找到，继续游戏。如果未找到，请更改布尔标志变量以指示游戏结束并以平局结束。

public bool isFull(char[] arr){
    for (int i = 0; i < arr.GetLength(0); i++){
        for (int j = 0; j < arr.GetLength(1); j++){
            if (arr[i, j] == initial_value){
                //If array in row i and column j is equal to the inital
                //value, return true.
                return true;
            }
        }
    }
    return false;
}

对于你的第二个问题，我会把把一块放入电路板的动作变成一个单独的功能，这将检查我之前提到的标志。如果该标志等于＆＃34; true＆＃34;，则不允许该动作发生。我建议以这种方式设置标志：

public void placeGamePiece(Player p){
    if (gameEndFlag == false){
        //Do the turn
    }

    else
        Console.WriteLine("The game is over!"); //Or any other print 
                                                //function you are using.
}

public void startGame(){
    public bool gameEndFlag = false;
    //..........
    gameEndFlag = !isFull(GameBoard);
}

我希望我以足够的方式回答你所有的问题。如果您需要对我在此处撰写的任何内容进行任何澄清，请与我们联系。如果你还没有学习循环和函数，我建议你现在就学习它们。

c＃Tic Toc Tow确定绘制

2 个答案: