Question

我正试图绕过Swift代表并偷走/敲打一个Playground，但似乎无法调用委托函数。

protocol fBookDelegate:class {
    func processData(data: String)
}

class fBook {

weak var delegate: fBookDelegate?

init() {
    print("initialising fBook")
    delegate?.processData(data: "hello world")
    print("we should have printed")
    }
}

class fMain: fBookDelegate {
init() {
    print("initialising fMain")
    let getfBook = fBook()
    getfBook.delegate = self
    print("all done let's rumble")
    }

func processData(data: String) {
    print("processing data from fBook with \(data)")
    }
}

var controller = fMain()

有人能发现我的错误吗？

我得到的所有输出都是

initialising fMain
initialising fBook
we should have printed
all done let's rumble

Answer 1

您可以这样使用：

import UIKit
protocol fBookDelegate:class {
    func processData(data: String)
}
class fBook {
    init(delegate: fBookDelegate?) {
        print("initialising fBook")
        delegate?.processData(data: "hello world")
        print("we should have printed")
    }
}
class fMain: fBookDelegate {
    init() {
        print("initialising fMain")
        let getfBook = fBook(delegate: self)
        print("all done let's rumble")
    }
    func processData(data: String) {
        print("processing data from fBook with \(data)")
    }
}

var controller = fMain()

输出：

initialising fMain
initialising fBook
processing data from fBook with hello world
we should have printed
all done let's rumble

Answer 2

以下是使用您的代理人的一个选项：

protocol fBookDelegate:class {
    func processData(data: String)
}

class fBook {

    weak var delegate: fBookDelegate?

    init() {
        print("initialising fBook")
    }

    func talkToMe() {
        delegate?.processData(data: "hello world")
    }
}

class fMain: fBookDelegate {
    init() {
        print("initialising fMain")
        let getfBook = fBook()
        getfBook.delegate = self
        getfBook.talkToMe()
        print("all done let's rumble")
    }

    func processData(data: String) {
        print("processing data from fBook with \(data)")
    }
}

var controller = fMain()

另一种方法是将委托作为参数的自定义init方法。

没有调用Swift 3 Delegate函数

2 个答案: