Question

如何使用scala测试比较两个列表列表？

val actual = Array(Row("1", "2"), Row("3", "4"))
val fail_expected = Array(Row("1", "2"), Row("3", "2"))
val pass_expected = Array(Row("3", "4"), Row("1", "2"))

我试过

actual should contain theSameElementsAs pass_expected

但它没有用，它说这两个数组是不同的，当它们实际上是相同的时候。

我正在使用带有scala测试的funsuite。

Answer 1

见working with containers。您需要通过以下任一方式为元素Row类实现相等性：

标准的Scala方式，如：

class Row(val elems: String*) {

    def canEqual(other: Any): Boolean = other.isInstanceOf[Row]

    override def equals(other: Any): Boolean = other match {
      case that: Row =>
        (that canEqual this) &&
          elems == that.elems
      case _ => false
    }

    override def hashCode(): Int = {
      val state = Seq(elems)
      state.map(_.hashCode()).foldLeft(0)((a, b) => 31 * a + b)
    }
}
object Row {
    def apply(elems: String*) = new Row(elems: _*)
}

或简单地将其作为案例类：

case class Row(elems: String*)

或提供隐式Equality[Row]实施：

import org.scalactic.Equality
implicit object RowEquals extends Equality[Row] {
    override def areEqual(a: Row, b: Any): Boolean = b match {
      case r: Row => a.elems == r.elems
      case _ => false
    }
}

Answer 2

快速但不是最好的解决方案是将数组转换为字符串。您可以使用mkstring方法实现它：

简而言之：

 actual.mkstring(",") == pass_expected.mkstring(",")

使用scala测试比较嵌套列表

2 个答案: