struct Data {
var DT: Date?
var D1: Double
var D2: Double
var D3: Double
var D4: Double
var I1: Int
}
var data = [Data]()
var format = "yyyyMMdd;%f;%f;%f;%f;%d"
var test = "20170924;1.1;2.2;3.3;4.4;100"
使用test
将data
的值设置为format
的最简单方法是什么?
ps:格式的分隔符可以是“,”或其他。
答案 0 :(得分:1)
您可以使用以下函数来获取已填充的Data
对象:
func getDesiredData(formattedString: String, dateFormat: String, separator: String) -> Data? {
let array = formattedString.components(separatedBy: separator)
//print(array.count)
if array.count < 6 {
// something went wrong seprating the formatted string
return nil
}
guard let d1 = Double(array[1]), let d2 = Double(array[2]), let d3 = Double(array[3]), let d4 = Double(array[4]), let i1 = Int(array[5]) else {
// something went wrong when converting string to doubles/int
return nil
}
var formatter = DateFormatter()
formatter.dateFormat = dateFormat
let date = formatter.date(from: array[0])
return Data(DT: date, D1: d1, D2: d2, D3: d3, D4: d4, I1: i1)
}
正如您在函数签名中所看到的,您可以自由添加所需的内容:
formattedString
,例如:“yyyyMMdd;%f;%f;%f;%f;%d”。dateFormat
,例如:“yyyyMMdd”。separator
,例如:“,”或“;”。输出:
// happy case ";":
let test1 = getDesiredData(formattedString: "20170924;1.1;2.2;3.3;4.4;100", dateFormat: "yyyyMMdd", separator: ";")
dump(test1)
// happy case ",":
let test2 = getDesiredData(formattedString: "20170924,1.1,2.2,3.3,4.4,100", dateFormat: "yyyyMMdd", separator: ",")
dump(test2)
// wrong format:
let test3 = getDesiredData(formattedString: "wrong;format;goes;here", dateFormat: "yyyyMMdd", separator: ";")
dump(test3) // nil
// wrong separator:
let test4 = getDesiredData(formattedString: "20170924;1.1;2.2;3.3;4.4;100", dateFormat: "yyyyMMdd", separator: "!")
dump(test4) // nil