Question

试图让它成为最大的任务在打印中被指出。得到其他一切只需要能够抓住最大的任务。

def main ():
    print("*** TIME MANAGEMENT ASSISTANT ***") NumberOfTasks = int(input("Number of tasks: "))
    total = 0.0
    TotalHour = 0.0
    Day = 0.0
    Minute = 0.0
    EndTimeMinute = 0.0
    EndTimeHour = 0.0
    EndTimeDay = 0.0
    RemainingHour = 0.0
    AverageMinutes = 0.0print("What time will you start (on a 24-hour clock)? ")
    StartHour = int(input("Hour: "))
    StartMinute = int(input("Minute: "))
    for i in range (NumberOfTasks):
        TaskName = input("Task description: ")
        TaskTime = int(input("How many minutes will this task take? "))
        total = int(total + TaskTime)
        TotalHour = int(total//60)
        Minute = int(total%60)
        Day = int(TotalHour//24)
        RemainingHour = int(TotalHour%24)
        EndTimeDay = Day
        EndTimeHour = TotalHour + StartHour
        if EndTimeHour > 24:
            EndTimeHour = int(total%60)
        EndTimeMinute = Minute + StartMinute
        AverageMinutes = float(total//NumberOfTasks)
    print("TOTAL TIME:", Day, "day(s)", RemainingHour, "hour(s)", Minute, "minute(s)")
    print("END TIME: ", "In ", EndTimeDay, " day(s) at ", EndTimeHour, ":", EndTimeMinute,sep="")
    print("LONGEST TASK: ")
print("AVERAGE TASK LENGTH:", round(AverageMinutes,2),  "minutes")

Answer 1

您需要记录每个“任务”的时间，然后通过排序来计算循环后的最长时间。要实现这种方式，您需要确保任务名称是唯一的，因此我添加了一行代码来做到这一点（所有添加的内容均已注释）：

def main():
    print("*** TIME MANAGEMENT ASSISTANT ***")
    NumberOfTasks = int(input("Number of tasks: "))
    total = 0.0
    TotalHour = 0.0
    Day = 0.0
    Minute = 0.0
    EndTimeMinute = 0.0
    EndTimeHour = 0.0
    EndTimeDay = 0.0
    RemainingHour = 0.0
    AverageMinutes = 0.0
    print("What time will you start (on a 24-hour clock)? ")
    StartHour = int(input("Hour: "))
    StartMinute = int(input("Minute: "))

    # create a dictionary to store time for each task
    task_times = {}

    for i in range (NumberOfTasks):
        TaskName = input("Task description: ")

        # ensure task name is unique
        while TaskName in task_times.keys():
            TaskName = input("Task description has already been used. Please enter a unique description: ")


        TaskTime = int(input("How many minutes will this task take? "))
        total = int(total + TaskTime)
        TotalHour = int(total//60)
        Minute = int(total%60)
        Day = int(TotalHour//24)
        RemainingHour = int(TotalHour%24)
        EndTimeDay = Day
        EndTimeHour = TotalHour + StartHour
        if EndTimeHour > 24:
            EndTimeHour = int(total%60)
        EndTimeMinute = Minute + StartMinute
        AverageMinutes = float(total//NumberOfTasks)

        # record time for this task in the dictionary
        task_times[TaskName] = TaskTime


    print("TOTAL TIME:", Day, "day(s)", RemainingHour, "hour(s)", Minute, "minute(s)")
    print("END TIME: ", "In ", EndTimeDay, " day(s) at ", EndTimeHour, ":", EndTimeMinute, sep="")

    # calculate longest task by sorting by time and taking the last item
    longest_task_name, longest_task_length = sorted(task_times.items(), key=lambda x: x[1])[-1]

    print("LONGEST TASK: {}".format(longest_task_name))
    print("AVERAGE TASK LENGTH:", round(AverageMinutes,2),  "minutes")

寻找最高价值的任务。除此之外什么都有

1 个答案: