.model small
.stack 100h
.data
tempax dw ?
tempdx dw ?
num dw ?
.code
.startup
push '@' ; initializing values
mov tempax,0
mov tempdx,0
mov num,0
mov cx,0
mov dx,0
read: ; taking input
mov ah,01h
int 21h
mov ah,0
cmp al,13
je disp
Mov ch, 0
sub al,48
mov cl,al
mov ax,0
mov ax,num
clc ;clearing flag as rcl shifts value of flag to lsb
rcl ax,1
rcl dx,1
mov tempax,ax ; save value of once shifted register as we to use it ahead
mov tempdx,dx ; user 2 register to accommodate 32 bit number
clc
rcl ax,1
rcl dx,1
clc
rcl ax,1
rcl dx,1
clc
add ax,tempax ; adding once shifted register with thrice shifted register
adc dx,tempdx ; tc of any carry
clc
add al,cl ; now adding number taken from user to result.
adc dl,0 ; again taking care of carry
mov num,ax ; saving ax to num
jmp read
disp:
mov ax,num
mov bx,0 ; bx is used to save the remainder
add bx,48
disp1:
clc
rcr dx,1
rcr ax,1
rcl bx,1 ;shifts value of carry flag to bx
cmp ax,tempax
je poppy ; to stop loop
mov tempax,ax ; saving once shifted register
mov tempdx,dx
clc
rcr dx,1
rcr ax,1
rcl bx,1
clc
rcr dx,1
rcr ax,1
rcl bx,1
clc
xchg tempax,ax
sub ax,tempax ; subtracting once shifted with 3 times shifted register
xchg tempdx,dx
sub dx,tempdx
push bx ; as bits are shifted they are saved in bx abd then pushed to stack
jmp disp1
poppy:
pop dx
cmp dx,'@'; end of stack check
je exit
sub dx,48 ;converting back to ascii
mov ah,02h
int 21h
jmp poppy
exit:
mov ah,04ch
mov al,0
int 21h
end
首先，我从用户输入一个带有中断功能的输入01h将其与输入键进行比较（输入的代码为13）然后我将ASCII值转换为其绝对值。如果我们左移3次并将其添加到左移的数字，一旦它相当于数字* 10。之后我添加用户输入的数字。如果我想显示输入，则1,2变为12.now必须通过分割它们并将其发送到堆栈来取出每个字符。然后使用poppy函数显示数字，但它显示一些乱码字符。我尝试添加并减去48即转换为ASCII。该程序运行时没有语法错误，有一个我无法找到的逻辑错误