Question

Swift 4中的混合不再有效。

Method 'initialize()' defines Objective-C class method 'initialize', which is not permitted by Swift

我已经找到了一个解决方案，所以想留下问题并回答其他人。

Answer 1

不再公开initialize（）：Method 'initialize()' defines Objective-C class method 'initialize', which is not permitted by Swift

所以现在的方法是通过公共静态方法运行你的混合代码。

例如

在扩展中：（此扩展用于kickstarted开源代码：https://github.com/kickstarter/ios-oss/blob/master/Library/DataSource/UIView-Extensions.swift）

private var hasSwizzled = false

extension UIView {
    final public class func doBadSwizzleStuff() {
        guard !hasSwizzled else { return }

        hasSwizzled = true
        swizzle(self) /* This is pseudo - run your method here */
    }
}

在app委托中：（此方法用于kickstarted开源代码：https://github.com/kickstarter/ios-oss/blob/7c827770813e25cc7f79a28fa151cd713efe936f/Kickstarter-iOS/AppDelegate.swift#L33）

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: UIApplicationLaunchOptionsKey: Any]?) -> Bool 
{
    UIView.doBadSwizzleStuff()
}

另一种方法是使用单身人士：

extension UIView {
    static let shared : UIViewController = {
        $0.initialize()
        return $0
    }(UIViewController())

    func initialize() {
        // make sure this isn't a subclass
        guard self === UIViewController.self else { return }

        let swizzleClosure: () = {
            UIViewController().swizzle() /* This is pseudo - run your method here */
        }()
        swizzleClosure
    }
}

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: UIApplicationLaunchOptionsKey: Any]?) -> Bool 
{
    _  = UIViewController.shared
}

方法在swift 4中调整

1 个答案: