Question

我想问一个用户：
如果他们画了一张王牌，问他们是否希望它是1或11。他们回答一个整数，将它设置为1或11是很重要的。不幸的是，当我运行时，它仍然是ace。

import time
import random
from random import *

suits = ["Hearts","Diamonds","Clubs","Spades"]
cards = ["Ace","2","3","4","5","6","7","8","9","10","Jack","Queen","King"]

def drawcard():
    global newcardtype
    global newcardsuit
    global newcard
    newcardtype = cards[randint(0,11)] ##User interface & Console
    newcardsuit = suits[randint(0,3)] ##User interface & Console
    newcard = newcardtype, newcardsuit ##Console to read and understand
    print("You picked up: " + str(newcardtype) + " of " + str(newcardsuit) + ".")

suits[0] = "♡"
suits[1] = "♢"
suits[2] = "♧"
suits[3] = "♤"    

cards[10] = 10
cards[11] = 10
cards[12] = 10

while(True):
    test = input("New card? ")
    if test == "y":
        drawcard()
        if newcardtype == cards[0]:
            acequestion = int(input("You picked up an Ace. Would you like your Ace to be 1 or 11?: "))
            if acequestion == 1:
                cards[0] = int(1)
            if acequestion == 11:
                cards[0] = int(11)
        print(newcardtype)

它处于正常工作状态，但我想cards[0]根据“acequestion”问题的答案，“ace”等于1或11。

Answer 1

您要将号码1或11分配给cards[0]，但这不会更改newcardtype引用的对象或值，因此它仍然具有值'ace'。如果您想更改newcardtype的值，您还必须为其分配1或11。

将整数分配给列表

1 个答案: