我是新来的火花,我有数据帧df:
+----------+------------+-----------+
| Column1 | Column2 | Sub |
+----------+------------+-----------+
| 1 | 2 | 1 |
+----------+------------+-----------+
| 4 | null | null |
+----------+------------+-----------+
| 5 | null | null |
+----------+------------+-----------+
| 6 | 8 | 2 |
+----------+------------+-----------+
当减去两列时,一列具有null,因此生成的列也导致为null。
df.withColumn("Sub", col(A)-col(B))
预期输出应为:
+----------+------------+-----------+
| Column1 | Column2 | Sub |
+----------+------------+-----------+
| 1 | 2 | 1 |
+----------+------------+-----------+
| 4 | null | 4 |
+----------+------------+-----------+
| 5 | null | 5 |
+----------+------------+-----------+
| 6 | 8 | 2 |
+----------+------------+-----------+
我不想将column2替换为0,它应该只为null。 有人可以帮我吗?
答案 0 :(得分:5)
您可以将when
功能用作
import org.apache.spark.sql.functions._
df.withColumn("Sub", when(col("Column1").isNull, lit(0)).otherwise(col("Column1")) - when(col("Column2").isNull, lit(0)).otherwise(col("Column2")))
你应该得到最终结果
+-------+-------+----+
|Column1|Column2| Sub|
+-------+-------+----+
| 1| 2|-1.0|
| 4| null| 4.0|
| 5| null| 5.0|
| 6| 8|-2.0|
+-------+-------+----+
答案 1 :(得分:2)
您可以coalesce
在两列上归零,然后进行减法:
val df = Seq((Some(1), Some(2)),
(Some(4), null),
(Some(5), null),
(Some(6), Some(8))
).toDF("A", "B")
df.withColumn("Sub", abs(coalesce($"A", lit(0)) - coalesce($"B", lit(0)))).show
+---+----+---+
| A| B|Sub|
+---+----+---+
| 1| 2| 1|
| 4|null| 4|
| 5|null| 5|
| 6| 8| 2|
+---+----+---+