Question

我有项目列表

<li><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));"></span></li>
<li><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));"></span></li>
<li><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));"></span></li>
<li><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));"></span></li>
<li><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));"></span></li>

和功能

function removeAnswer(that) {
  console.log(that.parent().eq()); <-- I need know which element is clicked
  that.parent().remove();
}

您知道我如何阅读eq项中removeAnswer项的内容吗？我无法在函数中传递第二个值，因为这是我的主脚本的一部分

我需要这个

console.log(that.parent().eq());

Answer 1

通过这种方式，您可以检测到要移除的项目（我已将id添加到li元素以进行演示）：

function removeAnswer(that) {
  console.log(that.parent().attr('id'));
  that.parent().remove();
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<li id="one"><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));">1</span></li>
<li id="two"><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));">2</span></li>
<li id="three"><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));">3</span></li>
<li id="four"><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));">4</span></li>
<li id="five"><span class="glyphicon-remove glyphicon removeAnswerCount" onclick="removeAnswer($(this));">5</span></li>

Answer 2

试试这个：

function removeAnswer(that) {
  console.log($(".glyphicon-remove").index(that))
}

如果单击第4个答案，则会打印出3，因为index（）会在that元素集合中返回从零开始的.glyphicon-remove索引。

在这里演示：https://jsfiddle.net/2bxc62tx/

Answer 3

您可以使用UPDATE _gtemp X JOIN _gtemp Y ON X.gt_spid = Y.gt_spid AND X.gt_cov = Y.gt_cov AND Y.gt_dna = 0 SET X.gt_dna = 1 WHERE Y.gt_gtid < X.gt_gtid方法。

index

jQuery是哪个eq类

3 个答案: