Question

在表数据之前：

-----------------------
|ID |WORK|VALUE|TOTAL|
-----------------------
|ID1|WRITE  |10 |   |
|ID1|TYPE   |5  |   |
|ID2|READ   |25 |   |
|ID2|SCAN   |30 |   |
|ID3|PRINT  |15 |   |
|ID4|SETTING|20 |   |
|ID5|REPAIR |5  |   |
|ID5|MAINTE |25 |   |
|ID5|MONITOR|20 |   |

总计是来自同一身份的总和值

ID1     10+5
ID2     25+30
ID3     15
ID4     20
ID5     50

现在我将insert方法与create table data2（ID，TOTAL）

一起使用

INSERT INTO DATA2(DATA2.ID, DATA2.TOTAL)
    SELECT DATA.ID, SUM (DATA.VALUE) AS TOTAL
    FROM DATA
    GROUP BY DATA.ID

然后我做SELECT JOIN FROM DATA2 AND DATA

表数据后

-----------------------
|ID |WORK|VALUE|TOTAL|
-----------------------
|ID1|WRITE  |10 |15 |
|ID1|TYPE   |5  |15 |
|ID2|READ   |25 |55 |
|ID2|SCAN   |30 |55 |
|ID3|PRINT  |15 |15 |
|ID4|SETTING|20 |20 |
|ID5|REPAIR |5  |50 |
|ID5|MAINTE |25 |50 |
|ID5|MONITOR|20 |50 |

Answer 1

要将值total更新为table，您需要拥有列..

alter table tblname
add total int

如果这不是一次性的方法，我建议创建一个如下所示的视图

create view somename
as
    select id,work,value,
    sum(value) over (partition by id ) as total
    from tabel

如果您想将表更新为一次性练习

;with cte
as
(select id,work,value,
sum(value) over (partition by id ) as total1
from tablename
)
update t
set t.total=c.total1
from cte c
join tablename t
on t.id=c.id

Answer 2

更新总计的另一种方法。

dispatch.yaml

DEMO

如何：使用SQL Server 2014中相同表中的sum列更新列？

2 个答案: