Question

在我的代码中，我试图从文本文件中获取一个数字列表，并找到其中最小的一个。我该怎么做？

Myfile = open("RoundOneTotalScores.txt","r")

AScore = ()
BScore = ()
CScore = ()
DScore = ()
EScore = ()
FScore = ()

for line in Myfile:
    if "A" in line.split(',')[0]:
        AScore = line.split(',')[1]

for line in Myfile:
    if "B" in line.split(',')[0]:
        BScore = line.split(',')[1]

for line in Myfile:
    if "C" in line.split(',')[0]:
        CScore = line.split(',')[1]

for line in Myfile:
    if "D" in line.split(',')[0]:
        DScore = line.split(',')[1]

for line in Myfile:
    if "E" in line.split(',')[0]:
        EScore = line.split(',')[1]

for line in Myfile:
    if "F" in line.split(',')[0]:
        FScore = line.split(',')[1]


list1 = [AScore, BScore, CScore, DScore, EScore, FScore]

int(list1)
smallest = min(list1)
print(smallest)

Myfile.close()

不断出现的错误是： Traceback（最近一次调用最后一次）：文件“”，第1行，in EliminateR1（）在EliminateR1中输入第39行的文件“D：\ NEA Real \ Test3.py” INT（列表1） TypeError：int（）参数必须是字符串，类字节对象或数字，而不是'list'

Answer 1

这是一个例子，假设您的数据看起来像这样。如果您想要最低限度，可以使用min。如果你想要两个最小的值，你可以sort列表并选择前两个：

txt = """A,1
B,3
F,5
D,4
C,2"""

values = [int(line.split(',')[1]) for line in txt.splitlines()]
print(values)
# [1, 3, 5, 4, 2]
print(min(values))
# 1
print(sorted(values))
# [1, 2, 3, 4, 5]
print(sorted(values)[:2])
# [1, 2]

如果您从文件中读取，则可以使用：

with open("RoundOneTotalScores.txt") as f:
    lines = f.readlines()
values = [int(line.split(',')[1]) for line in lines]
print(values)
# [1, 3, 5, 4, 2]
print(min(values))
# 1
print(sorted(values))
# [1, 2, 3, 4, 5]
print(sorted(values)[:2])
# [1, 2]
print(sorted(values)[2:])
# [3, 4, 5]

请注意，列表，字典和集合等集合已定义，因此您无需定义AScore，BScore，...

从文本文件中查找列表中的最小数字：Python

1 个答案: