foreach循环中的PHP JSON编码

Question

我试图生成以下JSON数据：

<div class="row video-section">
  @if(!(count($videos) > 0))
  <div class="col-md-12">
    <p>{{ $player->first_name }} {{ $player->last_name }} has no videos yet.</p>
  </div>
  @else
  @foreach($videos as $video)
  <div class="col-md-3 profile-video-box">
    <a href="/player/video/{{ $video->uid }}/{{ $video->player->fullName }}">
      <div class="card bg-dark text-white">
        <img src="{{ $video->getThumbnail() }}" class="card-img"/>
        <div class="card-img-overlay">
          <div class="play-icon-wrapper">
            <i class="ion-ios-play"></i>
          </div>
          <div class="card-content">
            <h5 class="card-title">{{ $video->title != '' ?  $video->title : 'Untitled' }}
            </h5>
            <p class="card-text">{{ $video->created_at->diffForHumans() }}
            </p>
          </div>
        </div>
      </div>
    </a>
  </div>
  @endforeach
</div> 

来自PHP [ { "ID": "A1000", "name": "John Simpson", "serialID": "S41234", "tagID": "ABC6456" }, { "ID": "B2000", "name": "Sally Smith", "serialID": "B5134536", "tagID": "KJJ451345" }, { "ID": "A9854", "name": "Henry Jones", "serialID": "KY4239582309", "tagID": "HYG452435" } ] 循环，如下所示：

foreach

我尝试过使用：

foreach($records as $record) {

        $ID = $record->getField('propertyID');
        $name = $record->getField('assignedName');
        $serialID = $record->getField('serial');
        $tagID = $record->getField('tag');

    }

适用于循环中的每条记录，但不能解决语法将它们连接成一个JSON数据字符串吗？

Answer 1

问题： - 您在$arr循环内每次覆盖foreach()变量。导致问题。

解决方案： - 而不是覆盖，请将值分配给数组，如下所示： -

$arr = []; //create empty array

foreach($records as $record) {

    $arr[] = array(
                'ID' => $record->getField('propertyID');
                'name' => $record->getField('assignedName');
                'serialID' => $record->getField('serial');
                'tagID' => $record->getField('tag')
            );//assign each sub-array to the newly created array
} 
echo json_encode($arr);

Answer 2

将记录添加到某种聚合数组，然后json_encode：

$items = [];
foreach($records as $record) {
    $items[] = [ 
        'ID' => $record->getField('propertyID'),
        'name' = $record->getField('assignedName'),
        'serialID' => $record->getField('serial'),
        'tagID' => $record->getField('tag'),
    ];
}

echo json_encode($items);

Answer 3

试试这个：

'rules' => [
    [
        'actions' => ['index', 'view'],
        'allow' => true,
        'roles' => [RbacComponent::VIEW_EXPENSES_ACCOUNTS_KEY],
    ],
    [
        'actions' => ['create'],
        'allow' => true,
        'roles' => [RbacComponent::CREATE_EXPENSES_ACCOUNTS_KEY],
    ],
    [
        'actions' => ['update'],
        'allow' => true,
        'roles' => [RbacComponent::EDIT_EXPENSES_ACCOUNTS_KEY],
    ],
    [
        'actions' => ['delete'],
        'allow' => true,
        'roles' => [RbacComponent::DELETE_EXPENSES_ACCOUNTS_KEY],
    ],
    [
        'actions' => ['index', 'view', 'create', 'update', 'delete'],
        'allow' => true,
        'matchCallback' => function ($rule, $action) {
            return \Yii::$app->user->identity->isOwner();
        },
    ],
],

说明：创建一个数组，将所有值放在其中一个数字索引上，并在循环中$data= array(); foreach($records as $record) { $data[] = array( 'ID' => $record->getField('propertyID'); 'name' => $record->getField('assignedName'); 'serialID' => $record->getField('serial'); 'tagID' => $record->getField('tag') ); } echo json_encode($data); 。

Answer 4

您可以使用类似array_map()的内容：

$result = array_map(function ($record) {
    return [
        'ID'       => $record->getField('propertyID'),
        'name'     => $record->getField('assignedName'),
        'serialID' => $record->getField('serial'),
        'tagID'    => $record->getField('tag'),
    ];
}, $records);

echo json_encode($result);

Answer 5

<?php
$ArrayName = array();

foreach($records as $record) {

        $ID = $record->getField('propertyID');
        $name = $record->getField('assignedName');
        $serialID = $record->getField('serial');
        $tagID = $record->getField('tag');

$ArrayName[] = array('ID' => $ID, 'name' => $name, 'serialID' => $serialID, 'tagID' => $tagID); //assign each sub-array to the newly created array

    }
echo json_encode($ArrayName);

?

> Blockquote

Answer 6

此代码可以帮助您：

<?php
$resultArray = array();

foreach($records as $record) 
{
        $newResultArrayItem = array();
        $newResultArrayItem['ID'] = $record->getField('propertyID');
        $newResultArrayItem['name'] = $record->getField('assignedName');
        $newResultArrayItem['serialID'] = $record->getField('serial');
        $newResultArrayItem['tagID'] = $record->getField('tag');

        $resultArray[] = $newResultArrayItem;
}

$encodedArray = json_encode($ArrayName);

echo $encodedArray;

?>