Question

这是我第一次在这里发帖，虽然我在这里阅读了很多很棒的技巧和技巧。

这是我的目标：

我有2个有点类似的表来比较。对于每个表的每一行，我将我想要的字段拉入一个数组。

我基本上想要从一个表中回显出任何数组的值，这些表在另一个数组中具有匹配的值。

这是我的代码，也许它会更容易理解。

$sql = "SELECT * FROM $i_comp ORDER BY `manufacturer`";
$statement = $objDb->query($sql);
$c_skus = $statement->fetchAll(PDO::FETCH_ASSOC);

$sql = "SELECT `sku_one`,`sku_two`,`qty`,`manufacturer`";
$sql .= "FROM $i_gas ORDER BY `manufacturer`";
$statement = $objDb->query($sql);
$d_skus = $statement->fetchAll(PDO::FETCH_ASSOC);

foreach ( $c_skus as $c_sku ) {
    // i want to see if any values of this array exist in the array created hy
    // the foreach loop below (yes, repeat for each row)
    $c = array($c_sku['sku'],$c_sku['sku_one'],$c_sku['sku_two'],$c_sku['sku_three']);
    foreach ( $d_skus as $d_sku ) {
        $d = array($d_sku['sku_one'],$d_sku['sku_two']);
        $intersect = array_intersect($c, $d);
        echo '<pre>', print_r($intersect), '</pre>';
    }
}

以下是我每次迭代代码时收到的结果：

Array
(
)
1

还应该注意的是，我并不关心Keys，只关注价值观。最终，这些值将被用于INSERT语句，但目前我只需要获得正确的结果。

无论如何，感谢任何和所有的帮助！

Answer 1

这通常在SQL

中完成

如果您希望整行在另一个表中至少有一个匹配的SKU：

$sql = "
SELECT c.* FROM $i_comp AS c 
  JOIN $i_gas AS d 
    ON d.sku_one in (c.sku, c.sku_one, c.sku_two, c.sku_three) 
    OR d.sku_two in (c.sku, c.sku_one, c.sku_two, c.sku_three) 
 ORDER BY c.`manufacturer`";
$statement = $objDb->query($sql);
$c_skus = $statement->fetchAll(PDO::FETCH_ASSOC);
// all rows that have at least 1 matching sku on another table
print_r($c_skus);

如果您只想要SKU

$sql = "
SELECT d.sku_one FROM $i_comp AS c 
  JOIN $i_gas AS d 
    ON d.sku_one in (c.sku, c.sku_one, c.sku_two, c.sku_three) 
UNION
SELECT d.sku_two FROM $i_comp AS c 
  JOIN $i_gas AS d 
    OR d.sku_two in (c.sku, c.sku_one, c.sku_two, c.sku_three) 
 ";
$statement = $objDb->query($sql);
$c_skus = $statement->fetchAll(PDO::FETCH_ASSOC);
// all skus that have at least 1 matching sku on another table
print_r($c_skus);

在PHP交叉变体中，您需要单独构建数组，然后使用array_intersect

$c = array();
foreach ( $c_skus as $c_sku ) {
    $c[] = $c_sku['sku'];
    $c[] = $c_sku['sku_one'];
    $c[] = $c_sku['sku_two'];
    $c[] = $c_sku['sku_three'];
}
$d = array();
foreach ( $d_skus as $d_sku ) {
    $d[] = $d_sku['sku_one'];
    $d[] = $d_sku['sku_two'];
}

$intersect = array_intersect($c, $d);
echo '<pre>', print_r($intersect), '</pre>';

foreach循环中的array_intersect

1 个答案: