功能：重命名和处理

Question

所以我在Python中试图找出这个语句时遇到了麻烦。通过重新键入celsius_to_kelvin函数。并将名称更改为kelvin_to_celsius。

def celsius_to_kelvin(value_celsius):
    value_kelvin = 0.0

    value_kelvin = value_celsius + 273.15
    return value_kelvin


value_c = 0.0
value_k = 0.0

value_c = 10.0
print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = 283.15
print(value_k, 'is', kelvin_to_celsius(value_k), 'C')

Answer 1

def celsius_to_kelvin(value_celsius):
    value_kelvin = 0.0

    value_kelvin = value_celsius + 273.15
    return value_kelvin

def kelvin_to_celsius(value_kelvin):
    value_c = 10.0
    
    value_c = value_kelvin -273.15
    return value_c

value_c = 10.0
print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = float(input())
print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')

Answer 2

def kelvin_to_celsius(value_kelvin):
    value_celsius = 0.0
    
    value_celsius = value_kelvin - 273.15
    return value_celsius

Answer 3

尝试一下：

def celsius_to_kelvin(value_celsius):
    value_kelvin = 0.0

    value_kelvin = value_celsius + 273.15
    return value_kelvin

def kelvin_to_celsius(value_kelvin):
    value_c = 0.0
    
    value_c = value_kelvin -273.15
    return value_c
    
    

value_c = 10.0
print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = float(input())
print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')

Answer 4

def celsius_to_kelvin(value_celsius):
    value_kelvin = 0.0

    value_kelvin = value_celsius + 273.15
    return value_kelvin

def kelvin_to_celsius(value_kelvin):
    value_celsius = 0.0

    value_celsius = value_kelvin - 273.15
    return value_celsius

value_k = 10.0

value_c = 10.0
print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = float(input())
print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')