我有以下jbehave故事文件:
ref.orderByChild('createdAt').startAt(Date.now()).on('child_added', ...
现在我想测试我的程序中的两个场景,所以我写了下面的代码:
Scenario: Scene1
Given the number of <input>
When the result is estimated
Then the result will be <expected>
Examples:
|input|expected|
|1|1|
|2|1, 2|
|3|1, 2, 3|
|4|1, 2, 3, 4|
Scenario: Scene2
Given the number of <input>
When the result is estimated
And the result is sorted in descending order
Then the result will be <expected>
Examples:
|input|expected|
|1|1|
|2|2, 1|
|3|3, 2, 1|
|4|4, 3, 2, 1|
当我运行测试用例时,我收到以下错误消息:
org.jbehave.core.steps.Steps $ DuplicateCandidateFound:那么结果 将是预期的
测试这两种情况的正确方法是什么,我在Java代码中需要做哪些更改。我不想改变我的故事档案。
这是我的JBehave配置文件:
import static org.junit.Assert.assertEquals;
import java.util.List;
import org.jbehave.core.annotations.Given;
import org.jbehave.core.annotations.Then;
import org.jbehave.core.annotations.When;
public class EstimatorSteps {
private Estimator estimator;
@Given("the number of $input")
public void given(int input) {
estimator = new Estimator(input);
}
@When("the result is estimated")
public void when1() {
estimator.estimate(estimator.getInput());
}
@Then("the result will be $expected)
public void then1(List<Integer> result) {
assertEquals(estimator.getResult(), result);
}
@When("the result is sorted in descending order")
public void when2() {
estimator.descending(estimator.getResult());
}
@Then("the result will be $expected)
public void then1(List<Integer> result) {
assertEquals(estimator.getResult(), result);
}
}
答案 0 :(得分:2)
EstimatorSteps
类中有两个相同的@Then步骤:
@Then("the result will be $expected)
public void then1(List<Integer> result) {
assertEquals(estimator.getResult(), result);
}
....
@Then("the result will be $expected)
public void then1(List<Integer> result) {
assertEquals(estimator.getResult(), result);
}
和JBehave抱怨:
DuplicateCandidateFound: THEN the result will be $expected
删除其中一种方法,不会出现错误。
BTW我想知道这个类是如何编译的,因为Java不应该允许两个具有完全相同签名的重载方法。