我有以下内容,我想通过按字母顺序排序,即每个数组的第一个是" bname",然后是" created_at"。
{
"leads": [
{
"lead_id": 1,
"zoho_lead": null,
"bname": "ABC Limited",
"tname": "ABC",
"source_id": 11,
"industry_id": 1,
"user_id": 1,
"created_at": "2017-09-06 15:54:21",
"updated_at": "2017-09-06 15:54:21",
"user": "Sean McCabe",
"source": "Unknown",
"industry": "None"
},
{
"lead_id": 2,
"zoho_lead": 51186111981,
"bname": "Business Name Limited",
"tname": "Trading Name",
"source_id": 11,
"industry_id": 1,
"user_id": 1,
"created_at": "2017-06-01 12:34:56",
"updated_at": null,
"user": "John Doe",
"source": "Unknown",
"industry": "None"
}
]
}
我试图在foreach循环中使用ksort:
class LeadController extends Controller
{
use Helpers;
public function index(Lead $leads)
{
$leads = $leads->all();
foreach($leads as $key => $lead){
$lead->user = User::where('id', $lead->user_id)->first()->name;
$lead->source = Source::where('id', $lead->source_id)->first()->name;
$lead->industry = Industry::where('id', $lead->industry_id)->first()->name;
$lead->ksort();
}
return $leads;
}
但是我收到以下错误:
Call to undefined method Illuminate\\Database\\Query\\Builder::ksort()
我如何使用此功能,或者是否有Laravel方式这样做,或者更好的方式?
感谢。
答案 0 :(得分:1)
管理以按字母顺序返回密钥,因此以下是其他人应该要求的解决方案:
public function index(Lead $leads)
{
$leadOut = Array();
$leads = $leads->all();
foreach($leads as $key => $lead){
$lead->user = User::where('id', $lead->user_id)->first()->name;
$lead->source = Source::where('id', $lead->source_id)->first()->name;
$lead->industry = Industry::where('id', $lead->industry_id)->first()->name;
//Convert to Array
$leadOrder = $lead->toArray();
//Sort as desired
ksort($leadOrder);
//Add to array
$leadOut[] = $leadOrder;
}
return $leadOut;
}
有一种更简洁的方法可以做到这一点,但它适用于我的实例,也许可能会发布更好的其他答案。
答案 1 :(得分:0)
您可以执行以下操作:
return Lead::with('user', 'source', 'industry')->get()->map(function ($lead) {
$item = $lead->toArray();
$item['user'] = $lead->user->name;
$item['source'] = $lead->source->name;
$item['industry'] = $lead->industry->name;
ksort($item);
return $item;
});
这应该更有效率,因为它会急切加载关系,而不是为每次迭代进行3次额外查询。