Question

嘿我正在使用XCode和iPhone 5c开发Cocos2dx应用程序，我希望将坐标系更改为肖像。我查看了这些方向http://www.cocos2d-x.org/wiki/Device_Orientation。根据方向，您需要在RootViewController中更改几个方法，以便在Cocos发挥其魔力之前，iOS已经处理了旋转容器。

现在我的RootViewController.mm的适用方法如下所示。它构建并运行。

#ifdef __IPHONE_6_0
- (NSUInteger) supportedInterfaceOrientations{
    return UIInterfaceOrientationMaskPortrait;
}
#endif

- (BOOL) shouldAutorotate {
    return YES;
}

- (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation {
    return UIInterfaceOrientationIsPortrait ( interfaceOrientation );
}

- (void)didRotateFromInterfaceOrientation:(UIInterfaceOrientation)fromInterfaceOrientation {
    [super didRotateFromInterfaceOrientation:fromInterfaceOrientation];

    auto glview = cocos2d::Director::getInstance()->getOpenGLView();

    if (glview)
    {
        CCEAGLView *eaglview = (__bridge CCEAGLView *)glview->getEAGLView();

        if (eaglview)
        {
            CGSize s = CGSizeMake([eaglview getWidth], [eaglview getHeight]);
            cocos2d::Application::getInstance()->applicationScreenSizeChanged((int) s.width, (int) s.height);
        }
    }
}
@end

我的关卡的init（）方法的代码如下所示

bool Level1::init()
{
    //////////////////////////////
    // 1. super init first
    if ( !Scene::init() )
    {
        return false;
    }

    auto visibleSize = Director::getInstance()->getVisibleSize();
    Vec2 origin = Director::getInstance()->getVisibleOrigin();

    for(int i= 0; i < MAX_TOUCHES; ++i) {
        labelTouchLocations[i] = Label::createWithSystemFont("", "Arial", 42);
        labelTouchLocations[i]->setVisible(false);
        this->addChild(labelTouchLocations[i]);
    }

    auto eventListener = EventListenerTouchAllAtOnce::create();

    //  Create an eventListener to handle multiple touches, using a lambda, cause baby, it's C++11
    eventListener->onTouchesBegan = [=](const std::vector<Touch*>&touches, Event* event){

        // Clear all visible touches just in case there are less fingers touching than last time
        std::for_each(labelTouchLocations,labelTouchLocations+MAX_TOUCHES,[](Label* touchLabel){
            touchLabel->setVisible(false);
        });

        // For each touch in the touches vector, set a Label to display at it's location and make it visible
        for(int i = 0; i < touches.size(); ++i){
            labelTouchLocations[i]->setPosition(touches[i]->getLocation());
            labelTouchLocations[i]->setVisible(true);
            labelTouchLocations[i]->setString("Touched");
            std::cout << "(" << touches[i]->getLocation().x << "," << touches[i]->getLocation().y << ")" << std::endl;

        }
    };

    _eventDispatcher->addEventListenerWithSceneGraphPriority(eventListener, this);

    return true;
}

当我触摸iPhone最左侧的点时，我打印出的触点的x坐标大约为150. y坐标为0，如预期的那样。为什么x坐标不为零？在场景的创作中是否有我遗漏的东西？我相信我做了Cocos文档所需的所有更改。他们的文档是否过时了？

Answer 1

坐标系不会从文档建议的左下角的（0,0）处开始。但是，有一些简单的方法可用于获取默认场景中包含的容器的原点和大小。

auto visibleSize = Director::getInstance()->getVisibleSize();
Vec2 origin = Director::getInstance()->getVisibleOrigin();

Cocos2dx v.3.0纵向模式

1 个答案: