Question

我为我的模型创建了一个视图，其中包含相应的网址和模板文件。然后，在管理面板中，我创建了一个富文本页面，指定了urlpatterns中定义的相同URL（成分）。夹层忽略视图，显示模板但不传递上下文。我该如何解决？

这些是代码：

models.py

from django.db import models
from mezzanine.pages.models import Page
from django.utils.translation import ugettext_lazy as _

class Ingredient(Page):
    name = models.CharField(max_length=60)
    information = models.TextField(null=True, blank=True, verbose_name=_("Description"))

views.py

from django.template.response import TemplateResponse
from .models import Ingredient

def ingredients(request):
    ingredients = Ingredient.objects.all().order_by('name')
    templates = ["pages/ingredients.html"]
    return TemplateResponse(request, templates, {'ingredients':ingredients})

urls.py

from django.conf.urls import url
from .views import ingredients

urlpatterns = [
    url("^$", ingredients, name="ingredients"),
]

Answer 1

TemplateResponse不期望其参数中的请求。请参阅the docs。

 return TemplateResponse(templates, {'ingredients':ingredients})

但是我希望你打算在那里使用标准render函数：

return render(request, "pages/ingredients.html", {'ingredients':ingredients})

Answer 2

好的，解决方案已经在我的项目urls.py文件中的任何其他定义之前定义了我的应用程序URL。

<强> PROJECT_NAME / PROJECT_NAME / urls.py

# Add the urlpatterns for any custom Django applications here.
# You can also change the ``home`` view to add your own functionality
# to the project's homepage.

urlpatterns = [
    url(r'^ingredients/', include("apps.ingredients.urls")),
]

urlpatterns += i18n_patterns(
    # Change the admin prefix here to use an alternate URL for the
    # admin interface, which would be marginally more secure.
    url("^admin/", include(admin.site.urls)),
)

夹层忽略视图，显示模板但不传递上下文

2 个答案: